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polet [3.4K]
4 years ago
6

Jack travels to work on the Eastern Freeway. He notices that the difference in time between if he drives 5 mph below the speed l

imit and if he drives 15 mph below the speed limit is 2 minutes. Given that the distance for which he uses the freeway is 10 miles, find the speed limit of the freeway.
55 mph
65 mph
60 mph
45 mph
Mathematics
2 answers:
QveST [7]4 years ago
5 0

Answer:

65 MPH

Step-by-step explanation:

Just took the test on Plato

#PlatoLivesMatter

Misha Larkins [42]4 years ago
3 0
Let's denote s as the speed limit. To find the total time it takes for Jack to drive given the speed, we just divide the total number of miles he covered (10 miles) by the speed he's traveling at.

Accounting for the given of the problem, we'll have the following equation:
\frac{10}{s-15} - \frac{10}{s-5}= \frac{1}{30} (from the fact that the difference between the time it takes to drive five miles below the speed limit versus 15 miles below is 2 mins or \frac{1}{30} hours.)

Since we only have one unknown variable, we can freely solve for s:
\frac{10}{s-15} - \frac{10}{s-5}= \frac{1}{30} 
\frac{10(s-5)-10(s-15)}{(s-15)(s-5)}= \frac{1}{30} 
\frac{10s-50-10s+150}{s^{2}-5s-15s+75}= \frac{1}{30} 
\frac{100}{s^{2}-20s+75}= \frac{1}{30}  
3000=s^{2}-20s+75
0=s^{2}-20s-2925
s_{1}=65
s_{2}=-45 (we ignore the negative value since there is no negative <u>speed</u>.)

ANSWER: The speed limit of the freeway is 65 mph.
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ValentinkaMS [17]

Answer:

a) Probability of a randomly sampled women not being qualified for the internship = 0.223

b) Probability that at least 30 percent of the women in the sample will not meet the age requirement for the internships = 0.03216

c) A woman who does not meet the age requirement is more likely to be selected with a stratified random sample than with a simple random sample.

Step-by-step explanation:

Age | Probability

17 | 0.005

18 | 0.107

19 | 0.111

20 | 0.252

21 | 0.249

22 | 0.213

23 or older | 0.063

a) Only 20+ year olds are qualified for the internship

So, probability of being qualified for the internship = P(x ≥ 20)

Probability of not being qualified for the internship = P(x < 20) = P(x=17) + P(x=18) + P(x=19) = 0.005 + 0.107 + 0.111 = 0.223

b) According to the Central limit theorem, a sampling distribution of sample size as large as 100 selected from this population distribution will approximate a normal distribution. It also has that

Mean proportion of sampling distribution of women who do not meet the internship requirements = Population proportion of women who do not meet the internship requirements = p = 0.223

The standard deviation of the is given by

σₓ = √[p(1-p)/n]

n = sample size = 100

σₓ = √[(0.223×0.777)/100] = 0.041625833 = 0.04163

So, to obtain the probability that at least 30 percent of the women in the sample will not meet the age requirement for the internships

P(x ≥ 0.30)

We first standardize 0.30

The standardized score for any value is the value minus the mean then divided by the standard deviation.

z = (x - μ)/σ = (0.30 - 0.223)/0.04163 = 1.85

The required probability

P(x ≥ 0.30) = P(z ≥ 1.85)

We'll use data from the normal probability table for these probabilities

P(x ≥ 0.30) = P(z ≥ 1.85) = 1 - P(z < 1.85)

= 1 - 0.96784 = 0.03216

c) Probability of women not meeting the internship requirements = 0.223

Probability of women meeting the internship requirements = 1 - 0.223 = 0.777

Or

Probability of women meeting the internship requirements = P(x ≥ 20)

= P(x=20) + P(x=21) + P(x=21) + P(x ≥ 23) = 0.777

But as the stratified sample only contains women who do not meet the internship requirements, it is more likely that A woman who does not meet the age requirement is selected with a stratified random sample than with a simple random sample.

Hope this Helps!!!

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3 years ago
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4 years ago
30 Points please help.
Rashid [163]
<h3>2 Answers: Choice C and Choice E</h3>

===================================================

Explanation:

θ = greek letter theta = reference angle

Using the unit circle, you should find that when θ is pi/3, we have

  • cos(θ) = cos(pi/3) = 1/2
  • sin(θ) = sin(pi/3) = sqrt(3)/2

Dividing sine over cosine gets us tangent

tan(θ) = sin(θ)/cos(θ) = sqrt(3)/2 divide over (1/2) = sqrt(3)

Effectively, the denominators '2' cancel out when dividing the two fractions. The result we get here is not sqrt(3)/2, so we can rule out choice A.

---------------

Choice B can be ruled out because

cos(0) = 1

sin(0) = 0

So,

tan(0) = sin(0)/cos(0) = 0/1 = 0

which doesn't match with y = pi

----------------

Following the same ideas as mentioned before:

cos(pi/4) = sqrt(2)/2

sin(pi/4) = sqrt(2)/2 ... it's not a typo, sine and cosine are the same here

tan(pi/4) = 1 after dividing the two items above

We end up with y = 1 as the screenshot shows, so (pi/4, 1) is one point on the graph of y = tan(x).

Choice C is one of the answers

----------------

Choice D however is not one of the answers because

sin(pi/2) = 1

cos(pi/2) = 0

tan(pi/2) = undefined, because the denominator cosine is 0 in this case

So there's a vertical asymptote at x = pi/2 for y = tan(x)

-----------------

Choice E is another answer, because,

sin(pi) = 0

cos(pi) = -1

tan(pi) = sin(pi)/cos(pi) = 0/(-1) = 0

This shows (pi, 0) is a point on y = tan(x).

The graph is shown below. Points C and E are on the blue tangent curve, while everything else isn't.

I used GeoGebra to create the graph. Desmos is also a handy tool that can perform similar tasks.

5 0
3 years ago
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dem82 [27]
Y-4-4x-3y=0
x-9-4x-3y=0
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2x+y+2=0
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x-1=0
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answer is c. -4
8 0
3 years ago
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