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2 years ago

) Bryan bought 25 pounds(lbs) of dog food but 10.4 pounds(lbs) spilled. How much did he have left?

2 answers:

7 0

14.6 pounds
25-10=15
Now from that you take one away and take 0.4 away from it and it will be 0.6 and then you add 14 and 0.6 and get 14.6

Scorpion4ik [409]2 years ago

5 0

Answer: 14.5

Step-by-step explanation: subtract the amount spilled from the total you had before. The amount spilled is not what he has anymore. Thus, he has 14.5 pounds.

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a right triangle has legs of length 3x m and 4x m and hypotenuse of length 75 m. find the lengths of the legs of the triangle

just olya [345]

It is a 3-4-5 right triangle

leg1 := 3x, leg2:=4x, hypotenuse:=5x

given hypotenuse = 75m
=> 5x=75
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2 years ago

12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5

Gnesinka [82]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle TPQ, 

RS || PQ,

RS = 3 cm,

PQ = 6 cm,

ar(∆ TRS) = 15 sq. cm

As it is given that, RS || PQ

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

$\rm\implies \: \triangle TPQ \: \sim \: \triangle TRS \: \: \: \: \: \: \{AA \}$

Now, We know 

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)} = \dfrac{ {PQ}^{2} }{ {RS}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{ {6}^{2} }{ {3}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{36 }{9}$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = 4$

$\rm\implies \:ar( \triangle \: TPQ) = 60 \: {cm}^{2}$

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VARVARA [1.3K]

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