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TiliK225 [7]
3 years ago
8

Find the sum of 2.005, 35.7 and 406​

Mathematics
2 answers:
Ann [662]3 years ago
5 0

Answer:

443.705

Step-by-step explanation:

andreev551 [17]3 years ago
4 0
443.705 is the sum of numbers
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A ferry traveled 1/6 of the distance between two ports in 3/7 hour at this rate what fraction of the distance between the two po
Masja [62]
First, we determine the speed of the ferry by dividing the distance by the time it took to cover that certain distance. 
                                 speed = (1/6) / (3/7)
                                   speed = 7/18
Then, the distance it will travel for an hour is calculated through the procedure below. 
                         distance = (7/18hour) x (1 hour)
                           distance = 7/18
Therefore, after an hour, the ferry will be able to travel 7/18 of the distance between two ports. 
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3 years ago
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A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa
diamong [38]

Answer:

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

Solution to the problem

The hypothesis for this case are:

Null hypothesis: \mu_{A}=\mu_{B}=\mu_{C}= \mu_D

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=A,B,C,D

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have p=4 groups and on each group from j=1,\dots,p we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}  

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

8 0
3 years ago
Is it possible for y to be an independent variable?????????
Ahat [919]
No. Hope this helps!
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3 years ago
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Find the values of x and y. PLEASEEE QILL GIVE BRAINLIEST
agasfer [191]

As parallel sides

\\ \rm\longmapsto 2x+90=180

\\ \rm\longmapsto 2x=90

\\ \rm\longmapsto x=90/2=45

Now

\\ \rm\longmapsto 2x+3y+6y+90=360

\\ \rm\longmapsto 9y+180=360

\\ \rm\longmapsto 9y=180

\\ \rm\longmapsto y=20

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Cooper is taking a multiple choice test with a total of 80 points available. Each question is worth exactly 4 points. What would
VLD [36.1K]

Answer:

80-4(2)=72; 80-4(x) if he got x wrong.

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3 years ago
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