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3 years ago

Can someone help me with this please

Mathematics

1 answer:

Stels [109]3 years ago

8 0

Your answer is 90$ hope this helps and sorry if it’s wrong

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Write an expression, using an exponent, that is equivalent to 9\times 9\times 9\times 9\times 9\times 9\times 99×9×9×9×9×9×9

jeka57 [31]

Nine to the eighth power

7 0

3 years ago

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Hey! Can someone check my answers?

Andrew [12]

The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
$20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}$
Since $x^{a}* x^{b} =x^{a+b}$ , then $x^{9}= x^{3}* x^{6}$

Back to our expression:
$4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+ 5y ^{6}*1=5 y^{6} (4y ^{3} +1)$
The greatest common factor is thus $5 y^{6}$

Q2. The answer is <span>D. 12xy^2
</span>
$12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}$
We will use the rule $x^{a}* x^{b} =x^{a+b}$ to factorise the exponents:
$12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)$
The greatest common factor is thus $12xy^{2}$

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3 years ago

What is the area of a right triangle with a base of 25 centimeters and a height of 13 centimeters?

sdas [7]

Answer:

<h3>162.5 cm²</h3><h3>Step-by-step explanation:</h3>

Area of a triangle = (BH)/2

Base= 25

Height=13

(25×13)/2= 162.5 cm²

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3 years ago

What is the solution set to 6+2n>12 Is n >3

Stolb23 [73]

6 + 2n > 12 |subtract 6 from both sides

2n > 6 |divide both sides by 2

n > 3

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3 years ago

What are the solutions of this equation? x^ - x - 56 = 0

NikAS [45]

Answer:

y = 0

Step-by-step explanation:

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3 years ago

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