Non-example of discrimination
1 answer:
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32 different combinations of three cars can the Carsons select if all the cars are to be different colors.
B. 32
<u>Explanation:</u>
As it is given there are four available colours of the car. That means we have 4 cars. . Now choose the first car. The no.of way of choosing the first car is equalled to 8 and imagine the first car Colour is black. Now we have a black car so we have to choose from 6 options apart from black.
Now no.of way of choosing the 2 car = 6 and imagine it is blue. Now we have to choose two colour car, so now we have 4 options to choose from. The no.of choosing the car = 4. Now let's calculate the total arrangement - . It is the total calculation for three cars.
But we have to know the selection so three cars can also be arranged in 6 ways. So the number of different combinations of three cars can be calculated as 192÷6= 32. This is how the selection is being done.