1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
deff fn [24]
2 years ago
12

An organic farm has been growing an heirloom variety of summer squash. A sample of the weights of 40 summer squash revealed that

the mean weight is 402.7 grams and the standard deviation 8.8 grams. What is the probability that the mean weight for a sample of 40 summer squash exceeds 405.5 grams?
a. 0.3783.
b. 0.0228.
c. 1.0000.
d. 0.5000.
Mathematics
1 answer:
natta225 [31]2 years ago
5 0

Answer:

b. 0.0228

Step-by-step explanation:

We are given that

n=40

Mean,\mu=402.7 g

Standard deviation, \sigma=8.8g

We have to find the probability hat the mean weight for a sample of 40 summer squash exceeds 405.5 grams.

P(x>405.5)=P(\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}>\frac{405.5-402.7}{\frac{8.8}{\sqrt{40}}})

P(x>405.5)=P(Z>\frac{2.8}{\frac{8.8}{\sqrt{40}}})

P(x>405.5)=P(Z>2.01)

P(x>405.5)=1-P(Z\leq 2.01)

P(x>405.5)=1-0.977784

P(x>405.5)=0.022216

Hence, option b is correct.

You might be interested in
Dan's school is selling tickets to a play. On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets
VashaNatasha [74]

Answer:

Let's define the variables:

A = price of one adult ticket.

S = price of one student ticket.

We know that:

"On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets for a total of $69."

1*A + 6*S = $69

"The school took in $150 on the second day by selling 7 adult tickets and student tickets"

7*A + 7*S = $150

Then we have a system of equations:

A + 6*S = $69

7*A + 7*S = $150.

To solve this, we should start by isolating one variable in one of the equations, let's isolate A in the first equation:

A = $69 - 6*S

Now let's replace this in the other equation:

7*($69 - 6*S) + 7*S = $150

Now we can solve this for S.

$483 - 42*S + 7*S = $150

$483 - 35*S = $150

$483 - $150 = 35*S

$333 = 35*S

$333/35 = S

$9.51 = S

That we could round to $9.50

That is the price of one student ticket.

4 0
3 years ago
point X is located at (2,-6), and point Z is located at (0,5). find the value for the point Y that is located 1/5 the distance f
HACTEHA [7]
Let point is(x,y)
x=(2-0)/5=2/5
y=(-6-5)/5=-11/5
(2/5,-11/5)
8 0
3 years ago
Brett and Max are diving. Brett is 34 feet below the surface and Max is 25 feet below the surface. How many feet above Brett isM
saveliy_v [14]

Answer:

Max is 9 ft above Brett

Step-by-step explanation:

Brett is 34 feet below the surface  = -34

Max is 25 feet below the surface = -25

Subtract the heights

-25 - -34

-25 +34

9

Max is 9 ft above Brett

6 0
3 years ago
Read 2 more answers
Is 5 right??!! If yes just put yes. If no explain and put what i should put.
Nana76 [90]
Yes 5 is right, good job
7 0
3 years ago
Please tell me answer of 6 7 and 8​
zloy xaker [14]

Answer:

6.angle m=180-60=120

7.angle y=180-(60+65)=55

8 0
3 years ago
Other questions:
  • 125 + .375=?<br><br><br> 0.654 + 0.389 - 0.293=?
    5·2 answers
  • Andrea made a replica of the Empire State Building. The surface area of the model is 45 ft2. What is the surface area of the act
    7·1 answer
  • Which is NOT a way to state the meaning of the expression x + 2?
    8·1 answer
  • Find area of shaded region of right triangle
    14·2 answers
  • Can some one answer this ?
    12·1 answer
  • √15(√6+6) A. √21+6√15 B. 3√10+6√15 C. √90+6 D. √90+6√15
    13·1 answer
  • Evaluate the expressions. -(1/3)^0 and (-9)^0​
    11·1 answer
  • Photos attached, please help. Brainliest will be given.
    12·2 answers
  • What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S
    7·1 answer
  • Identify the property: 15(1) = 15
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!