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Pavel [41]
3 years ago
13

Anybody good in geometry and know how to do this? Free Brainliest!!!

Mathematics
1 answer:
Anna007 [38]3 years ago
5 0

Answer:

A. -6, 4

Step-by-step explanation:

If the triangle is reflected across the y-axis, it's going to be in quadrant 2.

A is the only value located in quadrant 2. Therefore, -6, 4 will be point C's relfection.

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Find an equation of the line perpendicular to y = -1/2x – 3 that crosses the point
alisha [4.7K]

Answer:

<em>y = 2x + 4 </em>

Step-by-step explanation:

y = - \frac{1}{2} x - 3

Slope of perpendicular line is "2"

( - 3 , - 2 )

y + 2 = 2( x + 3 )

<em>y = 2x + 4</em>

6 0
3 years ago
What is the slope of a line perpendicular to y = -7/4x?
dexar [7]
A line is perpendiculat to another which has a slope of m if the perpendicular line has a slope of -1/m.
That means that if the product of slopes of two lines is -1, the two lines are perpendicular.

Here, y1=-7/4x, or m=-7/4
The perpendicular should have a slope of -1/m=-1/(-7/4)=4/7
6 0
3 years ago
To which graph does the point (−1, 3) belong? y ≥ 2x + 6 y ≥ 3x − 1 y ≥ −x + 3 y ≥ −2x + 5
Anna35 [415]
Well first find the slope of the point
y=mx+b  y=-1x+3
slope = -1
then put the problem in point slope form y - y1 = m (x-x1)
y + 3 = -1 (x+1) then solve for y=mx+b again
so y> 2x + 6 is the answer
4 0
3 years ago
Read 2 more answers
If f(x) = x-1/3 and g(x)= 3x+1, what is (f o g)(x)?
N76 [4]

Answer:

(f o g)(x) = 3x + \frac{2}{3}

Step-by-step explanation:

We have the function f(x) = x-\frac{1}{3} and we have the function g(x) = 3x + 1. We want to find g(x) composed with f(x)

Then, the function (f o g)(x) is the same since f(g(x))

That is, you must do x = g(x) and then enter g(x) into the function f(x).

f(g(x)) = (g(x)) -\frac{1}{3}

f(g(x)) = (3x + 1) -\frac{1}{3}

Simplifying, we obtain:

(f o g)(x) = 3x + 1 -\frac{1}{3}\\\\(f o g)(x) = 3x + \frac{2}{3}

Finally. The composite function is:

(f o g)(x) = 3x + \frac{2}{3}

6 0
3 years ago
Jane multiplies her number by three and subtracts 2.
katrin [286]

Answer:

Let the number they chose be 'x'.

Result of Jane = 3x -2

Result of Elliot = 2x+3

Given that,

The product of their result = 110

or, (3x-2)(2x+3) = 110\\or, 6x^{2} +9x-4x-6 = 110\\or, 6x^{2} +5x - 6 = 110\\or, 6x^{2} +5x - 6-110 = 0\\\\or, 6x^{2} +5x - 116 = 0\\or, 6x^{2} +29x - 24x - 116 = 0\\or, x (6x +29) -4(6x+29) = 0\\or, (x-4)(6x+29) = 0\\i.e. x=4 or x=\frac{-29}{6} \\So,~ the ~number ~they~ chose~was ~either ~4 ~or ~\frac{-29}{6}

3 0
3 years ago
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