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3 years ago

Anybody good in geometry and know how to do this? Free Brainliest!!!

Mathematics

1 answer:

Anna007 [38]3 years ago

5 0

Answer:

A. -6, 4

Step-by-step explanation:

If the triangle is reflected across the y-axis, it's going to be in quadrant 2.

A is the only value located in quadrant 2. Therefore, -6, 4 will be point C's relfection.

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Find an equation of the line perpendicular to y = -1/2x – 3 that crosses the point

alisha [4.7K]

Answer:

Step-by-step explanation:

y = - $\frac{1}{2}$ x - 3

Slope of perpendicular line is "2"

( - 3 , - 2 )

y + 2 = 2( x + 3 )

<em>y = 2x + 4</em>

6 0

3 years ago

What is the slope of a line perpendicular to y = -7/4x?

dexar [7]

A line is perpendiculat to another which has a slope of m if the perpendicular line has a slope of -1/m.
That means that if the product of slopes of two lines is -1, the two lines are perpendicular.

Here, y1=-7/4x, or m=-7/4
The perpendicular should have a slope of -1/m=-1/(-7/4)=4/7

6 0

3 years ago

To which graph does the point (−1, 3) belong? y ≥ 2x + 6 y ≥ 3x − 1 y ≥ −x + 3 y ≥ −2x + 5

Anna35 [415]

Well first find the slope of the point
y=mx+b y=-1x+3
slope = -1
then put the problem in point slope form y - y1 = m (x-x1)
y + 3 = -1 (x+1) then solve for y=mx+b again
so y> 2x + 6 is the answer

4 0

3 years ago

Read 2 more answers

If f(x) = x-1/3 and g(x)= 3x+1, what is (f o g)(x)?

N76 [4]

Answer:

$(f o g)(x) = 3x + \frac{2}{3}$

Step-by-step explanation:

We have the function $f(x) = x-\frac{1}{3}$ and we have the function $g(x) = 3x + 1$ . We want to find g(x) composed with f(x)

Then, the function (f o g)(x) is the same since f(g(x))

That is, you must do x = g(x) and then enter g(x) into the function f(x).

$f(g(x)) = (g(x)) -\frac{1}{3}$

$f(g(x)) = (3x + 1) -\frac{1}{3}$

Simplifying, we obtain:

$(f o g)(x) = 3x + 1 -\frac{1}{3}\\\\(f o g)(x) = 3x + \frac{2}{3}$

Finally. The composite function is:

$(f o g)(x) = 3x + \frac{2}{3}$

6 0

3 years ago

Jane multiplies her number by three and subtracts 2.

katrin [286]

Answer:

Let the number they chose be 'x'.

Result of Jane = $3x -2$

Result of Elliot = $2x+3$

Given that,

The product of their result = 110

$or, (3x-2)(2x+3) = 110\\or, 6x^{2} +9x-4x-6 = 110\\or, 6x^{2} +5x - 6 = 110\\or, 6x^{2} +5x - 6-110 = 0\\\\or, 6x^{2} +5x - 116 = 0\\or, 6x^{2} +29x - 24x - 116 = 0\\or, x (6x +29) -4(6x+29) = 0\\or, (x-4)(6x+29) = 0\\i.e. x=4 or x=\frac{-29}{6} \\So,~ the ~number ~they~ chose~was ~either ~4 ~or ~\frac{-29}{6}$

3 0

3 years ago