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2 years ago

What are the zeros for the function f(x) = (x + 7)(x + 5)

Mathematics

1 answer:

Svetllana [295]2 years ago

6 0

Answer:

(-7,0) and (-5,0)

Step-by-step explanation

1. 0= (x + 7)

-7 -7

-7=x

(-7,0)

2. 0= (x + 5)

-5 -5

-5=x

(-5,0)

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A rectangle has a width of x centimeters and a perimeter of 8x centimeters a square has sides of length 1/4 that of the length o

Amanda [17]

Answer:

Part A) The length of rectangle is $3x\ cm$

Part B) The perimeter of the square is $3x\ cm$

Part C) $20\ cm$

Part D) $39\ cm^{2}$

Step-by-step explanation:

Part A) Find the length of the rectangle

we know that

The perimeter of rectangle is equal to

$P=2(L+W)$

we have

$P=8x\ cm$

$W=x\ cm$

substitute and solve for L

$8x=2(L+x)$

$4x=(L+x)$

$L=4x-x=3x\ cm$

Part B) Find the perimeter of the square

we know that

The perimeter of a square is

$P=4b$

we have that

$b=(1/4)L$

substitute the value of L

$b=(1/4)3x=(3/4)x\ cm$

Find the perimeter of the square

$P=4(3/4)x=3x\ cm$

Part C) Find how many cm greater the rectangle's perimeter than the square's perimeter if x=4

Find the value of rectangle's perimeter

$P=8x\ cm$ ------> $P=8(4)=32\ cm$

Find the value of square's perimeter

$P=3x\ cm$ ------> $P=3(4)=12\ cm$

Find the difference

$32\ cm-12\ cm=20\ cm$

Part D) Find how many square cm greater the rectangle's area is than the square's area if x=4

Find the value of rectangle's area

$A=(3x)(x)=3x^{2}\ cm^{2}$ ------> $A=3(4^{2})=48\ cm^{2}$

Find the value of square's area

$A=((3/4)x)^{2}\ cm^{2}$ ------> $A=((3/4)(4))^{2}=9\ cm^{2}$

Find the difference

$48\ cm^{2}-9\ cm^{2}=39\ cm^{2}$

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3 years ago

What are the zeros for the function f(x) = (x + 7)(x + 5)​

What are the zeros for the function f(x) = (x + 7)(x + 5)