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Sonbull [250]
3 years ago
7

Given w1 = -2 + 3i and W2 = 4 - 4i, which complex number can be added to Wi to produce wz?

Mathematics
1 answer:
lyudmila [28]3 years ago
4 0

Given:

Two complex numbers are w_1=-2+3i and w_2=4-4i.

To find:

The complex number that can be added to w_1 to produce w_2.

Solution:

Let complex number z= is added to w_1 to produce w_2.

w_1+z=w_2

z=w_2-w_1

On substituting the values, we get

z=(4-4i)-(-2+3i)

z=4-4i+2-3i

Combine like real and imaginary parts.

z=(4+2)+(-4-3)i

z=6+(-7)i

z=6-7i

Therefore, the correct option is C.

You might be interested in
Label the parts of the equation 4x6=24
Alisiya [41]

The numbers are constants, and the multiplication symbol is an operator.

If this equation were 4x * 6 = 24, then 4 would be a coefficient and x would be a variable. 6 and 24 are still constants and the multiplication symbol is still an operator.

6 0
3 years ago
19b − -10b − -2b − -3b − 20b = 14<br><br> what does B=
Leona [35]

19b-(-10b)-(-2b)-(-3b)-20b = 14

14b=14 Simplify

b=1 Divide

You are posting a lot of these types of problems. Maybe the course you are taking is to difficult for you?

7 0
4 years ago
Read 2 more answers
How do I solve this
xz_007 [3.2K]

Let, the number of books I can buy = x

Selling price for 1 book = $5.99

So, selling price for x books = $(5.99x)

Given 7.5% is the sales tax.

To find sales tax we have to find 7.5% of $(5.99x)

7.5% of $(5.99x) = (5.99x) × 7.5/100 = (5.99x) × (0.075) = (0.44925x)

So the amount of sales tax = $(0.44925x)

The total cost for buying books including sales tax

= $(5.99x) + $(0.44925x)

=$(6.43925x)

Now given, the shipping cost is 10% of the price.

So to find the shipping cost we have to find 10% of $(6.43925x)

10% of $(6.43925x) = (6.43925x) × (10/100) = (6.43925x) ×(0.1) = (0.643925x)

Shipping charge = $(0.643925x)

So the total cost including shipping charge

= $(6.43925x) + $(0.643925x)

= $(7.083175x)

Now given, there is $50 to spend on books. So to find the number of books we can equate them.

7.083175x = 50

To get x, we have to divide both sides by 7.083175

(7.083175x)/7.083175 = 50/7.083175

x = 7.05898

As we are finding the number of books, so we will take the nearest whole number. Here the nearest whole number is 7.

So the required answer is 7 books.

3 0
4 years ago
A really bad carton of eggs contains spoiled eggs. An unsuspecting chef picks eggs at random for his ""Mega-Omelet Surprise."" F
Dima020 [189]

Answer:

(a) The probability that of the 5 eggs selected exactly 5 are unspoiled is 0.0531.

(b) The probability that of the 5 eggs selected 2 or less are unspoiled is 0.3959.

(c) The probability that of the 5 eggs selected more than 1 are unspoiled is 0.8747.

Step-by-step explanation:

The complete question is:

A really bad carton of 18 eggs contains 8 spoiled eggs. An unsuspecting chef picks 5 eggs at random for his “Mega-Omelet Surprise.” Find the probability that the number of unspoiled eggs among the 5 selected is

(a) exactly 5

(b) 2 or fewer

(c) more than 1.

Let <em>X</em> = number of unspoiled eggs in the bad carton of eggs.

Of the 18 eggs in the bad carton of eggs, 8 were spoiled eggs.

The probability of selecting an unspoiled egg is:

P(X)=p=\frac{10}{18}=0.556

A randomly selected egg is unspoiled or not is independent of the others.

It is provided that a chef picks 5 eggs at random.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.556.

The success is defined as the selection of an unspoiled egg.

The probability mass function of <em>X</em> is given by:

P(X=x)={5\choose x}(0.556)^{x}(1-0.556)^{5-x};\ x=0,1,2,3...

(a)

Compute the probability that of the 5 eggs selected exactly 5 are unspoiled as follows:

P(X=5)={5\choose 5}(0.556)^{5}(1-0.556)^{5-5}\\=1\times 0.05313\times 1\\=0.0531

Thus, the probability that of the 5 eggs selected exactly 5 are unspoiled is 0.0531.

(b)

Compute the probability that of the 5 eggs selected 2 or less are unspoiled as follows:

P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)

              =\sum\imits^{2}_{x=0}{{5\choose 5}(0.556)^{5}(1-0.556)^{5-5}}\\=0.0173+0.1080+0.2706\\=0.3959

Thus, the probability that of the 5 eggs selected 2 or less are unspoiled is 0.3959.

(c)

Compute the probability that of the 5 eggs selected more than 1 are unspoiled as follows:

P (X > 1) = 1 - P (X ≤ 1)

              = 1 - P (X = 0) - P (X = 1)

              =1-\sum\limits^{1}_{x=0}{{5\choose 5}(0.556)^{5}(1-0.556)^{5-5}}\\=1-0.0173-0.1080\\=0.8747

Thus, the probability that of the 5 eggs selected more than 1 are unspoiled is 0.8747.

6 0
3 years ago
$53.89 + 18% = ?????
Aneli [31]

Answer:

<u>=$63.59 OR 63.5902</u>

Step-by-step explanation:

53.89+18%

<u>=$63.59 OR 63.5902</u>

6 0
3 years ago
Read 2 more answers
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