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3 years ago

HELP PLEASEEEEEEEEEEEEE!

Mathematics

2 answers:

Kitty [74]3 years ago

5 0

Answer:

3.) x=3

4.) x=11

Step-by-step explanation:

3.) 80= 27x-1

x=3

4.) 5x+5+9x+21= 180

14x+26= 180

x=11

baherus [9]3 years ago

3 0

Answer: #3) x= 3. #4) x= 11

Step-by-step explanation:

For #3 these angles are alternate exterior angles. (Opposite sides of the transversal and outside of the parallel lines) Alternate exterior angles are equal, so set these two equal to each other to solve for x. 27x-1 = 80 Add 1 to both sides. 27x = 81. Divide both sides by 27. X = 3. For #4, these angles are same side interior angles. (Same side of the transversal and inside the parallel lines) Same side interior angles sum to 180 degrees. (5x+5) + (9x+21) = 180. Combine like terms. 14x + 26= 180. Subtract 26 from both sides. 14x = 154. Divide both sides by 14. X = 11

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Relations and Functions, please help with these 3 questions asap. I will give brainliest! Only answer if you know how to do this

gladu [14]

<h2> Question # 1</h2>

Part A) Is the relation a function? Explain.

A function relates each element of a set with exactly one element of another set.

Important things for a relationship to be a function:

Every element in X is related to some element in Y.

A function cannot have one-to-many relationship.

A function must contain single valued, means it is not having one-to-many relation

Considering the points on coordinate plane

(-4, 2), (-3, 0), (-2, -1), (0, 2), (2, -3), (3, 3)

If we carefully observe, we determine that relation

relates each element of a set with exactly one element of another set

is single-valued, means It is not giving back 2 or more results for the same input. In other words, it is not having one-to-many relation.

It is in fact, having many to one. For example, the pairs (0, 2) and (-4, 2) is having many- to-one relationship.

So, from the above observation, it is clear that the relationship is a function.

Part B) What is the domain of the relation?

Considering the points on coordinate plane

(-4, 2)

(-3, 0)

(-2, -1)

(0, 2)

(2, -3)

(3, 3)

Also we know that domain of the relation is the set of all the x-values of an ordered pairs.

So, the domain of the relation: {-4, -3, -2, 0, 2, 3}

Part C) What is the range of the relation?

Considering the points on coordinate plane

(-4, 2)

(-3, 0)

(-2, -1)

(0, 2)

(2, -3)

(3, 3)

As we know that the range of a relationship is the set of all the y-values of an ordered pair.

So, the range of the relationship will be: { -3, -1, 0, 2, 3}

Note:

The duplicated entries in the domain and range are written only once.
Also, the domain and range can be written in ascending order.

Part D) What is the value of y when x = 2? Explain

Considering the points on coordinate plane

(-4, 2)

(-3, 0)

(-2, -1)

(0, 2)

(2, -3)

(3, 3)

From the given points on the coordinate plane, it is clear that when the value of x = 2, then the value of y = -3

Therefore, the value of y is -2 when x = 2

<h2> Question # 2</h2>

Considering the points on coordinate plane

(-4, -1), (-2, 1), (0, -3), (2, 3), (4, -2)

If we bring a point, let say (2, 4), and graphed on the coordinate system, then the relation will no longer be function.

The reason is that the induction of the point (2, 4) would violate the definition of a relation to be a function.

Observe that (2, 4) and (2, 3) will make the relation having one-to-many relationship as (2, 4) and (2, 3) is giving 2 outputs i.e. y = 4, and y = 3 for a single input i.e. x = 2.

Therefore, the induction of the point (2, 4), when graphed, makes the relation not a function.

<h2> Question # 3</h2>

Part A)

$f\left(x\right)\:=\:|x\:-\:3|\:-\:2$ ; $x = -5$

The attached figure a shows the graph for the function

$f\left(x\right)\:=\:|x\:-\:3|\:-\:2$

In the attached figure a, the graph represents an absolute value relationship as the absolute value of a number is never negative.

Evaluate the function for x = -5

$f\left(x\right)\:=\:|x\:-\:3|\:-\:2$

$|\left-5\right\:-\:3|\:-\:2....[A]$

Solving

$\left|-5-3\right|$

$\mathrm{Subtract\:the\:numbers:}\:-5-3=-8$

$=\left|-8\right|$

$\mathrm{Apply\:absolute\:rule}:\quad \left|-a\right|=a$

$\left|-8\right|=8$

So,

$\left|-5-3\right|=8$

Equation [A] becomes

$\:|-5\:-\:3|\:-\:2\:=8\:-\:2\:$ ∵ $\left|-5-3\right|=8$

$=6$

Therefore,

the value of $f\left(x\right)\:=\:|x\:-\:3|\:-\:2$ at $x = -5$ will be 6.

i.e. $f(x)=6$

<h2 />

Part B)

$g\left(x\right)=1.5x;\:x=0.2$

The attached figure b shows the graph for the function

$g\left(x\right)=1.5x$

In the attached figure b, the graph shows that the function represents a linear relationship as the graph is a straight line.

Evaluate the function for x = 0.2

$g\left(x\right)=1.5x$

Putting x = 0.2

$g\left(x\right)=1.5\left(0.2\right)$

$1.5\left(0.2\right)=0.3$

$g\left(x\right)=0.3$

So,

the value of $g\left(x\right)=1.5x$ at $x = 0.2$ will be 0.3.

i.e. $g\left(x\right)=0.3$

Part C)

$p\left(x\right)\:=\:|7\:-\:2x|;\:x\:=\:-3$

As the absolute value of a number will be never negative.

The attached figure c shows the graph for the function

$p\left(x\right)\:=\:|7\:-\:2x|$

In the attached figure c, the graph represents an absolute value relationship as the absolute value of a number is never negative.

Evaluate the function for x = -3

$p\left(x\right)\:=\:|7\:-\:2x|$

Solving

$\left|7-2x\right|$

$\left|7-2\left(-3\right)\right|$

$=\left|7+6\right|$

$=\left|13\right|$

$\mathrm{Apply\:absolute\:rule}:\quad \left|a\right|=a,\:a\ge 0$

$=13$

So,

$\left|7-2x\right|=13$

So,

the value of $p\left(x\right)\:=\:|7\:-\:2x|$ at $x = -3$ will be 13.

i.e $p\left(x\right)\:=13$

Keywords: function, relation

Learn more about functions from brainly.com/question/2335371

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3 0

4 years ago

Give the expression 4n^2t/2n^t-1, write the expression as a binomial.

lubasha [3.4K]

binomial is an algebraic expression containing 2 terms. For example, (x + y) is a binomial.

We sometimes need to expand binomials as follows:

(a + b)0 = 1

(a + b)1 = a + b

(a + b)2 = a2 + 2ab + b2

(a + b)3 = a3 + 3a2b + 3ab2 + b3

(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4

(a + b)5 = a5 + 5a4b + 10a3b2 + 10a2b3 + 5ab4 + b5

Clearly, doing this by direct multiplication gets quite tedious and can be rather difficult for larger powers or more complicated expressions.

Pascal's Triangle

We note that the coefficients (the numbers in front of each term) follow a pattern. [This was noticed long before Pascal, by the Chinese.]

1 1

1 2 1

1 3 3 1

1 4 6 4 1

1 5 10 10 5 1

1 6 15 20 15 6 1

You can use this pattern to form the coefficients, rather than multiply everything out as we did above.

The Binomial Theorem

We use the binomial theorem to help us expand binomials to any given power without direct multiplication. As we have seen, multiplication can be time-consuming or even not possible in some cases.

Properties of the Binomial Expansion (a + b)nThere are \displaystyle{n}+{1}n+1 terms.The first term is an and the final term is bn.Progressing from the first term to the last, the exponent of a decreases by \displaystyle{1}1 from term to term while the exponent of b increases by \displaystyle{1}1. In addition, the sum of the exponents of a and b in each term is n.If the coefficient of each term is multiplied by the exponent of a in that term, and the product is divided by the number of that term, we obtain the coefficient of the next term.

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Step-by-step explanation:

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