All categories

3 years ago

Estimate the product by rounding 2×6,254

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

3 0

Answer:

12,500

Step-by-step explanation:

in 6,254 since your rounding the 4 would round down to a 0 so then you just multiply 2 by 6250 to get 12500

You might be interested in

Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

3 years ago

Given the following functions, find the indicated values.

allsm [11]

Answer:

A. f(-2)=3-6(-2)

-2f =3-(-12)

-2f=3+12

=15

divide both sides by 2

f=15/2

B. f(0)=3-6(0)

f=3

C.f(4)=3-6(4)

4f=3-24

f=21/4

5 0

2 years ago

Find the product. 2.05x0.47 =

pshichka [43]

Answer:

0.9625

Step-by-step explanation:

6 0

3 years ago

Omar has decided to purchase an $11,000 car. He plans on putting 20% down toward the purchase, and financing the rest at 4.8% in

Solnce55 [7]

Answer:

The monthly payment is $262.95

Step-by-step explanation:

* Lets explain how to solve the problem

- Omar has decided to purchase an $11,000 car

- He plans on putting 20% down toward the purchase

* Lets find the value of the 20%

∵ The principal value is $11000

∴ the value of the 20% = 20/100 × 11000 = 2200

∴ He will put $2200 down

* Lets find the balance to be paid off on installments

∴ The balance = 11000 - 2200 = 8800

- He financing the rest at 4.8% interest rate for 3 years

* Lets find the rule of the monthly payment

∵ $pmt=\frac{\frac{r}{n}[P(1+\frac{r}{n})^{nt}]}{(1+\frac{r}{n})^{nt}-1}$ , where

- pmt is the monthly payment

- P = the investment amount

- r = the annual interest rate (decimal)

- n = the number of times that interest is compounded per unit t

- t = the time the money is invested or borrowed for

∵ P = 8800

∵ r = 4.8/100 = 0.048

∵ n = 12

∵ t = 3

∴ $pmt=\frac{\frac{0.048}{12}[8800(1+\frac{0.048}{12})^{3(12)}]}{(1+\frac{0.048}{12})^{3(12)}-1}$

∴ $pmt=\frac{0.004[8800(1.004)^{36}]}{(1.004)^{36}-1}=262.95$

* The monthly payment is $262.95

8 0

3 years ago

The equations 2 x minus 5 y = negative 5, 11 x minus 5 y = 15, 9 x + 5 y = 5, and 14 x + 5 y = negative 5 are shown on the graph

Dafna11 [192]

Answer:

See attached graph

Step-by-step explanation:

8 0

3 years ago