Answer18:
The quadrilateral ABCD is not a parallelogram
Answer19:
The quadrilateral ABCD is a parallelogram
Step-by-step explanation:
For question 18:
Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)
The slope of a line is given m=
Now,
The slope of a line AB:
m=
m=
m=
The slope is 90 degree
The slope of a line BC:
m=
m=
m=
The slope is zero degree
The slope of a line CD:
m=
m=
m=
The slope is 90 degree
The slope of a line DA:
m=
m=
m=
m=
The slope of the only line AB and CD are the same.
Thus, The quadrilateral ABCD is not a parallelogram
For question 19:
Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)
The slope of a line is given m=
Now,
The slope of a line AB:
m=
m=
m=
The slope of a line BC:
m=
m=
m=
m=3
The slope of a line CD:
m=
m=
m=
The slope of a line DA:
m=
m=
m=3
The slope of the line AB and CD are the same
The slope of the line BC and DA are the same
Thus, The quadrilateral ABCD is a parallelogram
The required value is 8
How can we find value?
We will find the value by putting the value of w in the given function to get the required value.
We can find the value of given function foe w=2 as shown below:
Given, function is 2w+w^3-1/2w^2
Let A=2w+w^3-1/2w^2
for w=2
A=2(2)+(2)^3-1/2(2)^2
= 2+8-1/2(4)
=2+8-2
=8
Hence, the required value is 8.
Learn more about function here:
brainly.com/question/875118
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It is impossible to draw a parallelogram with 4 parallel lines (or to draw any quadrilateral with 4 parallel lines, for that matter).
Answer:

Step-by-step explanation:
The square root of 11 is 3.31... this could be the answer.