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BigorU [14]
2 years ago
12

True or false:

Mathematics
1 answer:
IgorC [24]2 years ago
3 0

Answer:

The degree of a binomial is zero. The product of two binomials is not a polynomial. The sum of two polynomials is a polynomial. A monomial containing ^2 has a degree of three

The degree of the polynomial is found by looking at the term with the highest exponent on its variable(s). Examples: 5x2-2x+1 The highest exponent is the 2 so this is a 2nd degree trinomial.

Names of Degrees

Degree Name Example

0 Constant 7

1 Linear x+3

2 Quadratic x2−x+2

3 Cubic x3−x2+5

The degree of a cubic monomial is three. A quadratic polynomial is a trinomial. The degree of a binomial is two.

Step-by-step explanation:

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Which inequality represents this sentence?
Natasha2012 [34]
The last answer is correct
5 0
2 years ago
Really struggling with this, can someone please help me out and give me a brief explanation? Id seriously appreciate it.
Bogdan [553]

Answer:

314 m²

Step-by-step explanation:

the surface area of a sphere (As) is

As = 4×pi×r²

our radius r (half of the diameter) here is 5m.

As = 4×3.14×5² = 4×3.14×25 = 100×3.14 = 314 m²

8 0
2 years ago
What is the difference between an irrational number and an integer?? please explain!
SpyIntel [72]

Answer:

Explanation: Irrational numbers are non-terminating, recurring decimal numbers i.e, a decimal expansion that neither terminates nor becomes periodic which cannot be expressed in the form of a fraction. ... Integer is a complete entity that includes every natural number along with its negatives and zero.

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
-7w+8 (w+1)=w-7<br> Please show work
kvv77 [185]
Hello there.^••^

−7w+8(w+1)=w−7
w+8=w−7
w+8−w=w−7−w8=−7
8−8=−7−80=−15
No solutions.
6 0
3 years ago
Read 2 more answers
Which of the following expressions is equal to 3x^2 + 27
Kisachek [45]
Factor: 
3x^2 + 27
= 3(x^2  + 9)
Answer is 3(x^2 + 9), when factored.


A) (3x + 9i)(x + 3i)
= (3x + 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + (9i)(x) + (9i)(3i)
= 3x^2 + 9ix + 9ix + 27i^2
= 27i^2 + 18ix + 3x^2



B) (3x - 9i)(x + 3i)
= (3x +  - 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + ( - 9i)(x) + (- 9i)(3i)
= 3x^2 + 9ix - 9ix - 27i^2
= 27i^2 + 3x^2


C) (3x - 6i)(x + 21i)
= (3x +  - 6i)(x + 21i)
= (3x)(x) + (3x)(21i) + (- 6i)(x) + ( -6i)(21i)
= 3x^2 + 63ix - 6ix - 126i^2
=  - 126i^2 + 57ix + 3x^2






D) (3x - 9i)(x - 3i)
=  (3x +   - 9)(x +  - 3)
= (3x)(x) + (3x)( - 3i) + (- 9)(x) + ( - 9)( - 3i)
= 3x^2 - 9ix - 9x + 27i
= 9ix + 3x^2 + 27i - 9x









Hope that helps!!!

8 0
3 years ago
Read 2 more answers
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