when the regular school year starts again, and you’re trying to remember more immediate deadlines for schoolwork assignments. Print out a calendar exclusively for keeping track of college application deadlines, school visits, and overnights, and place it in a central location to ensure that you’re always on top of where you need to be and what needs to be sent in.
2.Work on applications and essays in a designated workspace
Just as you might have a specific study area for when you do your homework, choose a spot in which you work only on your college applications and essays. It can be difficult to focus relaxing in your bedroom or in the kitchen with the television on, so consider setting aside a certain time to visit the library or stop in at the College Bound Admissions Academy classroom to ensure you get some work accomplished. Meeting deadlines rather than missing them is easier to do when you work ahead and concentrate.
3.Create a folder for each school
Because there are often entirely different sets of requirements for individual schools, get organized by making a file folder for each school. Keep promotional materials sent by the school in the folder, along with a master sheet of contact information for your admissions counselor and other people you have or may work with in other departments in the folder. Other information, such as logins and passwords for school websites and online applications should also be kept in the folder as well.
B. Includes a pledge of collateral
Answer:
m<MON = 100°
Explanation:
Given:
Area of shaded sector LOM = 2π cm²
NL = 6 cm
Required:
m<MON
Solution:
m<MON = 180° - m<LOM (angles in a straight line)
We don't know m<LOM. Therefore, let's find m<LOM.
Area of a sector = θ/360 × πr²
Area of sector LOM = 2π cm²
r = 3 cm
θ = m<LOM = ?
Plug in the values
2π = m<LOM/360 × π × 3²
2π = m<LOM/360 × 9π
2π = m<LOM × 9π/360
2π = m<LOM × π/40
Multiply both sides by 40
2π × 40 = m<LOM × π
80π = m<LOM × π
Divide both sides by π
80π/π = m<LOM
80 = m<LOM
m<LOM = 80°
✔️m<MON = 180° - m<LOM (angles in a straight line)
Substitute
m<MON = 180° - 80°
m<MON = 100°
The answer is the second choice, because (9) X 3 = 27.
Answer:
Force
Explanation:
A description and measurement of the interaction between the two objects.A push or a pull.Forces always exist in pairs.
