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Lyrx [107]
2 years ago
14

Light bulbs are normally distributed with an average lifetime of 1000 hours and a standard deviation of 250 hours. The probabili

ty that a light bulb picked at random will last between 1400 and 1500 hours is about:
Mathematics
1 answer:
Alexus [3.1K]2 years ago
4 0

Answer:

The probability that a light bulb picked at random will last between 1400 and 1500

P(14 00≤X≤1500) = 0.032

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that mean of the Population = 1000

Given that the standard deviation of the Population = 250 hours

Let 'X' be the random variable in a normal distribution

Let  X = 1400

Z = \frac{X-mean}{S.D} = \frac{1400-1000}{250} = 1.6

Let X = 1500

Z = \frac{X-mean}{S.D} = \frac{1500-1000}{250} = 2

The probability that a light bulb picked at random will last between 1400 and 1500

P(x₁≤ X ≤x₂) = P(Z₁≤ Z ≤z₂)

                   = A( Z₂ ) -A(Z₁)

P(1400≤X≤1500)  = P(1.6≤ Z ≤2)

                            =  A(2 ) -A(1.6)

                           =  0.4772-0.4452

                          = 0.032

<u><em>Final answer:</em></u>-

The probability that a light bulb picked at random will last between 1400 and 1500

P(14 00≤X≤1500) = 0.032

                   

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If 120% is £48, what is 100%
azamat

Answer:

40

Step-by-step explanation:

If we go by 20's (20% of 100) 100% is 5. Since were dealing with 120% in our case we'll be dividing by 6 <u>to figure out what every 20% is</u>. All we need to do it's divide 48 by 6 and we get the answer 8. So in our case every 20% is equal to 8. now to solve for 100% all we need to do is subtract 8 (20%) from 120% (48) and we find 100% is 40. We could also do 8 x 5. (<em>remember every 1 is 20% in our case</em>) which is also 40. Therefore, your answer is 40.

If you don't quite understand what I'm talking about please let me know and I'll elaborate.. thanks! have a nice day and good luck with your quiz!

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3 years ago
How many terms are there in the following expression:
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3 terms

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Whats an equation slop 0.5, passes through(6,4)
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What is the probability that a randomly selected male will have a foot length between 8 and 12.5 inches? P(8 &lt; r &lt; 12.5)=
melisa1 [442]

Answer:

0.8185 or 81.85%

Step-by-step explanation:

The mean length (μ) of an adult foot is 11 and the standard deviation (σ) is 1.5.

The z score is a measure in statistic used to determine the amount of standard deviation by which the raw score (x) is above or below the mean. If the raw score is above the mean, the z score is positive  and if the raw score is below the mean the z sore is negative. It is given by:

z=\frac{x-\mu}{\sigma}

To calculate the probability that a randomly selected male will have a foot length between 8 and 12.5 inches, we first calculate the z score for 8 inches and then for 12.5 inches.

For 8 inches:

z=\frac{x-\mu}{\sigma}=\frac{8-11}{1.5}=-2

For 12.5 inches:

z=\frac{x-\mu}{\sigma}=\frac{12.5-11}{1.5}=1

From the normal distribution table, The probability that a randomly selected male will have a foot length between 8 and 12.5 inches = P(8 < x < 12.5) = P(-2 < z < 1) = P(z < 1)  - P(z < -2) = 0.8413 - 0.0228 = 0.8185 = 81.85%

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What is 7/4 plus -1/2 plus 2/3? And what’s the answer
vichka [17]

Answer:

1.85

Step-by-step explanation:

1.75-0.5+0.6= 1.85 or 1 17/20

4 0
3 years ago
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