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Lyrx [107]
3 years ago
14

Light bulbs are normally distributed with an average lifetime of 1000 hours and a standard deviation of 250 hours. The probabili

ty that a light bulb picked at random will last between 1400 and 1500 hours is about:
Mathematics
1 answer:
Alexus [3.1K]3 years ago
4 0

Answer:

The probability that a light bulb picked at random will last between 1400 and 1500

P(14 00≤X≤1500) = 0.032

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that mean of the Population = 1000

Given that the standard deviation of the Population = 250 hours

Let 'X' be the random variable in a normal distribution

Let  X = 1400

Z = \frac{X-mean}{S.D} = \frac{1400-1000}{250} = 1.6

Let X = 1500

Z = \frac{X-mean}{S.D} = \frac{1500-1000}{250} = 2

The probability that a light bulb picked at random will last between 1400 and 1500

P(x₁≤ X ≤x₂) = P(Z₁≤ Z ≤z₂)

                   = A( Z₂ ) -A(Z₁)

P(1400≤X≤1500)  = P(1.6≤ Z ≤2)

                            =  A(2 ) -A(1.6)

                           =  0.4772-0.4452

                          = 0.032

<u><em>Final answer:</em></u>-

The probability that a light bulb picked at random will last between 1400 and 1500

P(14 00≤X≤1500) = 0.032

                   

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Step-by-step explanation:

The perimeter of a plane shape is the distance round the shape. The garden is rectangular in shape.

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The length of the garden is (2x – 5) feet and the width of the garden is (x + 3) feet. The length of fencing that Juan would need is

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Answer:

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\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

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Step-by-step explanation:

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