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o-na [289]
3 years ago
11

I need help please ​

Mathematics
1 answer:
zvonat [6]3 years ago
4 0
The correct answer is false:) Parallel lines don’t have a solution because they don’t intersect.
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Select the correct answer.
maks197457 [2]

Answer:

See Explanation

Step-by-step explanation:

Your question is poorly formatted. However, I'm able to deduce that your question involves at least 2 algebraic fractions that needs to be simplified.

So, I'll make use of the following expression:

\frac{3n}{n + 3} + \frac{5}{n - 4}

When you follow the steps I'm about to provide, you'll arrive at the right answer

Required

Determine an equivalent expression

\frac{3n}{n + 3} + \frac{5}{n - 4}

Step 1: Take L.C.M of the denominators

LCM = (n+3)(n-4)

Step 2: Evaluate the fractions

\frac{3n}{n + 3} + \frac{5}{n - 4} = \frac{3n(n-4)+5(n+3)}{(n+3)(n-4)}

Step 3: Open the brackets at the numerator

\frac{3n}{n + 3} + \frac{5}{n - 4} = \frac{3n^2-12n+5n+15}{(n+3)(n-4)}

Step 4: Collect and evaluate like terms

\frac{3n}{n + 3} + \frac{5}{n - 4} = \frac{3n^2-7n+15}{(n+3)(n-4)}

<em>Follow the above steps, and you'll be able to solve your question.</em>

6 0
3 years ago
1.Which postulate or theorem can you use to prove Triangle ABE = Triangle CDE?
stira [4]

Answer:

AAS Postulate.

Step-by-step explanation:

The AAS Postulate states that if 2 angles and a non-included side are congruent on both triangles, then the two triangles are equivalent.

In this case, the first Angle is: ∠B ≅ ∠D (Given, both are 90° in measurement)

For the side: Line BE ≅ line DE (Given)

∡BEA ≅ ∡DEC (Definition of Vertical Angles)

AAS Postulate is therefore used.

~

6 0
3 years ago
HEEEEELLLPPP ME PLEASE!!!!!!!!!!
mafiozo [28]

ANSWER

y \leqslant  \frac{1}{3}x - 4

EXPLANATION

First, find the equation of the boundary line which passes through the point

(3,-3) and has a y-intercept of -4.

The slope of this line is,

m =  \frac{ - 4 -  - 3}{0 - 3}  =  \frac{1}{3}

The equation of this line is

y =  \frac{1}{3}x - 4

Since the lower half plane is shaded and the boundary line is solid. The required inequality is

y \leqslant  \frac{1}{3}x - 4

5 0
3 years ago
Read 2 more answers
Please help me with this, anyone??
mart [117]

Answer:

I would say A

Step-by-step explanation:\pi \\

I'm saying its a because normally the Volume formula would be

V= h/3 (pi) r^2

so if it is doubled it should be

V=2/3 (pi) r^2

8 0
3 years ago
Simplify the sum. State any restrictions on the variables. (x-2)/(x+3) + (10x)/(x^(2)-9)
nlexa [21]
\frac{x-2}{x+3} + \frac{10x}{ x^{2} -9}= \\ = \frac{x-2}{x+3}+ \frac{10x}{(x-3)(x+3)}=
Restrictions are: x ≠ - 3,  x ≠ 3.
= \frac{(x+2)(x-3)+10x}{(x+3)(x-3)}= \\  \frac{ x^{2} -3x+2x-6+10x}{(x+3)(x-3)}= \\ = \frac{ x^{2} +9x-6}{(x+3)(x-3)}
6 0
3 years ago
Read 2 more answers
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