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seraphim [82]
2 years ago
12

Deja caer una pelota de una azotea de un edificio si tarda 4 segundos en llegar al piso, cual es la altura del edificio? Con que

velocidad choca contra el piso?
Spanish
1 answer:
Alexus [3.1K]2 years ago
4 0

Answer:

Dado que la bola se deja caer,

la velocidad inicial (sea u) = 0 m / s

Ahora, el tiempo para llegar a la calle es (t) = 4seg.

Y, aceleración de la partícula (a) = g (constante gravitacional universal)

= 9,8 m / s ^ 2

Ahora, como la aceleración de la partícula es constante durante todo el movimiento

usamos la fórmula,

S = ut + 1/2 × a × (t) ^ 2 (donde S = distancia recorrida por la partícula = altura del edificio)

S = (0) × 4 + 1/2 × (9,8) × (4) ^ 2

S = 0 + 9,8 × 8

= 78,4 millones.

Explanation:

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