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vodomira [7]
2 years ago
5

Find the slope of ( - 9,3) ( - 5,7)

Mathematics
2 answers:
kifflom [539]2 years ago
7 0

Answer:

m=1

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-9, 3)

Point (-5, 7)

<u>Step 2: Find slope </u><em><u>m</u></em>

Simply plug in the 2 coordinates into the slope formula to find slope <em>m</em>

  1. Substitute [SF]:                    m=\frac{7-3}{-5+9}
  2. Subtract/Add:                      m=\frac{4}{4}
  3. Divide:                                 m=1
shtirl [24]2 years ago
4 0

Answer:

The slope is 1

Step-by-step explanation:

Subtract 7 and 3 to get 4. Then subtract -5 and -9 to get 4. Lastly divide 4 and 4 to get your answer of 1.

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Answer:

if X is the angle degree like I think it is, then X = 56 degrees

Step-by-step explanation:

isosceles triangles will have 2 equal base angles.

90 degree angle - 28 = 62°

62 is now each base angle.

62 times 2 angles equals 124

the final angle, x, is 180 - 124 = 56°

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1 year ago
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3 years ago
What is the equation of the yellow line
katovenus [111]

Answer:

y = -\frac{5}{3} x -2

Step-by-step explanation:

The line is going down to the right so it has the negative slope, with a y- intercept of (0, -2) and a slope of m = rise/run = -5/3

6 0
3 years ago
3. (05.06 MC)
AveGali [126]

Answer:

Step-by-step explanation:

y > 3x + 10

y < -3x - 1

<h3> Part A:</h3>

You'd graph the given systems of linear inequalities the same way as you graph the linear equations.  

To graph y > 3x + 10, plot the y-intercept, (0, 10), then use the slope, m = 3 (rise 3, run 1), to plot other points on the graph.  Use a dashed line (because of the ">" symbol).  

Follow the same steps for the other linear inequality. Plot the y-intercept, (0, -1), then use the slope, m = -3 (down 3, run 1) to plot other points. Use a dashed line (because of the "<" symbol).  

Pick a test point on either side of the boundary line and plug it into the original problem.  This will help determine which side of the boundary line is the solution.  Plug in a test point that is not on the boundary line.

Use the point of origin, (0, 0) as the test point. Plug in these values into the given systems of linear inequalities to see whether it will provide a true statement.  

y > 3x + 10

0 > 3(0) + 10

0 > 0 + 10

0 > 10 (False statement).  

y < -3x - 1

0 < -3(0) - 1

0 < 0 - 1

0 < -1 (false statement).  

Since the point of origin provided a false statement to the given systems of linear inequalities, you must shade the half-plane region where it doesn't contain the test point.  

<h3>Part B: </h3>

You'll do the same process as what I've done for the test point. Plug in the values of (8, 10) into the given systems of linear inequalities. If it provides a false statement, then it means that it is not a solution to the system.  

y > 3x + 10

10 > 3(8) + 10

10 > 24 + 10

10 > 34 (False statement).  

y < -3x - 1  

10 < -3(8) - 1

10 < -24 - 1

10 < -25 (false statement).  

Therefore, (8, 10) is not a solution to the system.    

8 0
2 years ago
What is the relationship between the sine and cosine of complementary angles?
pochemuha
<span> Yes, there is a "relationship" regarding the </span>tangent<span> of the two acute angles (A and B) in a right triangle.</span>
8 0
3 years ago
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