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3 years ago

Which ordered pair is a solution? Select all that apply

Mathematics

1 answer:

Shkiper50 [21]3 years ago

6 0

Answer:

(10, 9) and (8, 1)

Step-by-step explanation:

you can just use substitution

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Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

A pool cover is 25 feet by 50 feet. What is its square area in meters?

Katyanochek1 [597]

Answer:

1250 m^2

Step-by-step explanation:

Area = 25 * 50 = 1250 m^2

8 0

3 years ago

The product of two whole numbers is 608 and their sum is 51 .what are the two numbers ?

amid [387]

Answer:

The product of 19 and 32 is 608 and their sum adds up to 51.

The two numbers are: 19 and 32

3 0

2 years ago

What is the solution to the equation 2x + 4 = 23x?

Cerrena [4.2K]

Answer:

x=4/21

Step-by-step explanation:

2x+4=23x

-2x -2x

4=21x

4/21=x

5 0

3 years ago

Can someone explain this please?

Greeley [361]

$\left( 8 \times 10^{-5}\right)\cdot \left( 5 \times 10^{-6}\right)\\ \\ =\left( 8 \times 5\right)\cdot \left( 10^{-5} \times 10^{-6}\right)$

1) first do the integer part $\left( 8 \times 5\right)=40$

2) then do the exponent part $\left( 10^{-5} \times 10^{-6}\right)$ = ???

3) Once you do the first two steps... adjust your answer to scientific notation...

3 0

3 years ago