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weeeeeb [17]
4 years ago
10

Please help need some help

Mathematics
1 answer:
Lemur [1.5K]4 years ago
3 0
The graph shows exponential growth. as the amount of people infected with the virus decreases, time decreases
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Jana pencil is 8.5cm long.teds pencil is longer.what is the length of Ted's pencil
Mumz [18]
This is not enough info to determine the length of teds pencil
3 0
4 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=Evaluate%20%20the%20Expression%3Cbr%3E%3Cbr%3E%0A%5Csqrt%7B%20%5Csqrt%5B4%5D%7B8%7D%201%7D%20%
Nezavi [6.7K]
Hello,

81^(1/8)+√169=13+√3≈14,73205....
===========================
6 0
3 years ago
Is (8, 8) a solution to the equation y = X?<br> Yes or No ?
Nataly [62]

Answer

YEAH

Explanation

The x value is 8.

The y value is 8.

Well...

8=8

So yes.

7 0
3 years ago
On the last three physics exams a student scored 89, 87, and 92. What score must the student earn on the next exam to have an av
OlgaM077 [116]

Answer:

For the average to be above 90, the marks in the fourth paper should be MORE THAN 92.

Step-by-step explanation:

The score of students in last 3 exams =  89 , 87 and 92

Let us assume the marks scored by the student in last exam = k

The average of marks should be above 90.

Now, \textrm{The average of total marks}  = \frac{\textrm{Sum of all marks obtained in 4 papers}}{\textrm{ 4 papers }}

Sum of all 4 paper's marks =  89 + 87 + 92 + k = 268 + k

Also, 90 <  Average

\implies 90 < \frac{268 + k}{4}\\ or, 360 < 268 + k\\\implies  360 - 268 < k\\or,  k >  92

Hence,for the average to be above 90, the marks in the fourth paper should be MORE THAN 92.

4 0
4 years ago
solve quadratic by taking square roots. as=a,-a where a and -a the values you found when when solving. Round to nearest tenth. 2
attashe74 [19]

Answer:

8.1

Step-by-step explanation:

2x^2 -9 = 121

        +9    +9

2x^2 = 130

/2         /2

x^2   = 65

x= sqrt (65)

x= 8.06225...

x = 8.1

6 0
3 years ago
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