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weeeeeb [17]
4 years ago
10

Please help need some help

Mathematics
1 answer:
Lemur [1.5K]4 years ago
3 0
The graph shows exponential growth. as the amount of people infected with the virus decreases, time decreases
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What is the sum?<br> 6x^7 + 8x^7
BaLLatris [955]
Since both terms have the same variable to the same power, you can simply add the coefficients...

14x^7
3 0
4 years ago
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14.7x + 4x = 0*(46y+39y) Y=14, Solve for X
Dovator [93]
14.7x + 4x = 0*(49y+39y) y = 14

18.7x = 0(686 + 546)

18.7x = 0

x = 0
4 0
3 years ago
A local florist buys a dozen roses for x dollars. He plans to sell the roses at a 40 % mark-up. What expression shows the sellin
Ira Lisetskai [31]

Answer:

1.40x I think :)

5 0
3 years ago
Which inequality represents the statement? The ages (a) of s group of travelers all exceeded 17 years and were no more then 54 y
klasskru [66]

Answer:

The inequality that represents the age of the group, "x", is: 17 < x \leq 54

Step-by-step explanation:

To express this problem in an inequality we will attribute the age of the members on the group with the variable "x". There are two available information about "x", the first states that every member of the group is older than 17 years, therefore we can create a inequality based on that:

x > 17

While the second data from the problem states that none of than is older than 54 years old, this implies that they can be at most that old, therefore the inequality that represents this is:

x\leq 54

In order for both to be valid at the same time x must be greater than 17 and less or equal to 54, therefore we finally have:

17 < x \leq 54

7 0
3 years ago
$700 is invested at 4% per annum. How long will it take for the amount to reach $784?​
Blababa [14]

Answer:

3yrs

Step-by-step explanation:

Given parameters:

Capital = $700

Percentage interest  = 4% per annum

Unknown:

Time it will take for amount to be  = $784

Solution:

To find the simple interest on an amount;

        I = \frac{PRT}{100}

P is the principal

R is the rate

T is the time

I is the interest

    Insert the parameters:

        I  = \frac{700x 4 x T}{100}

        I = 28T

So;

   At the end of the duration:

       Principal + Interest  = Amount

          700+28T = 784

                   28T = 784 - 700

                   28T = 84

                       T = 3yrs

5 0
3 years ago
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