All categories

3 years ago

Please solution and answer a and b thanks you

Mathematics

1 answer:

Igoryamba3 years ago

5 0

Answer:

A) 2280 and length is 12mm and width is 190mm

B) 190, 12

Step-by-step explanation:

Area of 1 cylinder: 456

456*5= 2280

38*5=190

diameter:190mm

height:12mm

190*12= 2280

You might be interested in

Evaluate the value of the expression<br>4(x+2-5x) when x=2

mart [117]

Answer:

-24

Step-by-step explanation:

plz mark brainlyest

6 0

3 years ago

What is the distributative answer to 85 divided by 5 answer

andrew11 [14]

85/5
(50+35)/5
50/5 + 35/5
10+7=17

6 0

3 years ago

A new car worth 24000 is depreciating in value by 3000 per year after how many years will the car be 12000

AveGali [126]

Answer:

4 years

Step-by-step explanation:

need to see how many times 3000 can go in 24000 and count how many years tell u get 12000

hopes I helped

7 0

3 years ago

Read 2 more answers

In a survey of 200 residents, 75 said they support the proposed town budget. If there are 10,000 total residents, about how many

Archy [21]

If 75 out of 200 people support the town budget than 3,750 out of 10,000 support it

7 0

3 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0

3 years ago

Please solution and answer a and b thanks you ​

Please solution and answer a and b thanks you