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3 years ago

How does a tree have self similarity?

1 answer:

4 0

Well trees are living things like humans they are very helpful like people they have arms like people and the leaves are kinda like hair

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Here are two shapes with the same area. Work out the perimiter of the rectangle.

Lilit [14]

So, we know the perimeter is 24 cm. and the top part is the left part, (x) + 2, but remember, we need to have it be a number that, multiplied by 2, is 24. So, using this formula, the length, (top / bottom) is 7, and x = 5. Because 5 + 5 = 10, and when length is +2, it adds up to 14. 10 + 14 = 24. So, length is 7, width, (left, right) is 5.

3 0

3 years ago

Select the equation that represents the following graph

stiks02 [169]

Answer:

there is nothing atttached or no options given

Step-by-step explanation:

3 0

3 years ago

What is the length of the hypotenuse of the triangle when x=15?

Luden [163]

Answer:

114.24°

Step-by-step explanation:

7(15)+6= 105

3(15)= 45, now we plug it in the formula, $a^{2}+b^{2}=c^{2}$

$105^{2}+45^{2} = 13050$

so now we square root it

$\sqrt{13050}$ = 114.24

6 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP! I don’t recall how to do this!

MakcuM [25]

Answer:

Step-by-step explanation:

For a. we start by dividing both sides by 200:

$(1.05)^x=1.885$

In order to solve for x, we have to get it out from its position of an exponent. Do that by taking the natural log of both sides:

$ln(1.05)^x=ln(1.885)$

Applying the power rule for logs lets us now bring down the x in front of the ln:

x * ln(1.05) = ln(1.885)

Now we can divide both sides by ln(1.05) to solve for x:

$x=\frac{ln(1.885)}{ln(1.05)}$

Do this on your calculator to find that

x = 12.99294297

For b. we will first apply the rule for "undoing" the addition of logs by multipllying:

$ln(x*x^2)=5$

Simplifying gives you

$ln(x^3)=5$

Applying the power rule allows us to bring down the 3 in front of the ln:

3 * ln(x) = 5

Now we can divide both sides by 3 to get

$ln(x)=\frac{5}{3}$

Take the inverse ln by raising each side to e:

$e^{ln(x)}=e^{\frac{5}{3}}$

The "e" and the ln on the left undo each other, leaving you with just x; and raising e to the power or 5/3 gives you that

x = 5.29449005

For c. begin by dividing both sides by 20 to get:

$\frac{1}{2}=e^{.1x}$

"Undo" that e by taking the ln of both sides:

$ln(.5)=ln(e^{.1x})$

When the ln and the e undo each other on the right you're left with just .1x; on the left we have, from our calculators:

-.6931471806 = .1x

x = -6.931471806

Question d. is a bit more complicated than the others. Begin by turning the base of 4 into a base of 2 so they are "like" in a sense:

$(2^2)^x-6(2)^x=-8$

Now we will bring over the -8 by adding:

$(2^2)^x-6(2)^x+8=0$

We can turn this into a quadratic of sorts and factor it, but we have to use a u substitution. Let's let $u=2^x$

When we do that, we can rewrite the polynomial as

$u^2-6u+8=0$

This factors very nicely into u = 4 and u = 2

But don't forget the substitution that we made earlier to make this easy to factor. Now we have to put it back in:

$2^x=4,2^x=2$

For the first solution, we will change the base of 4 into a 2 again like we did in the beginning:

$2^2=2^x$

Now that the bases are the same, we can say that

x = 2

For the second solution, we will raise the 2 on the right to a power of 1 to get:

$2^x=2^1$

Now that the bases are the same, we can say that

x = 1

5 0

3 years ago

PLEASE HELP!! A tennis ball machine serves a ball vertically into the air from a height of two feet, with an initial speed of 1

ch4aika [34]

Thank you for posting your question here. I hope the answer below will help.

Vo=110 feet per second
ho=2 feet 
So, h(t) = -16t^2 +110t +2 
Take the derivative: h'(t) = 110 -32t 
The maximum height will be at the inflection when the derivative crosses the x-axis aka when h'(t)=0. 
So, set h'(t)=0 and solve for t: 
0 = 110 -32t 
-110 = -32t 
t=3.4375 
t=3.44 seconds

4 0

3 years ago

Read 2 more answers