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IrinaVladis [17]
3 years ago
10

How does a tree have self similarity?

Mathematics
1 answer:
ankoles [38]3 years ago
4 0
Well trees are living things like humans they are very helpful like people they have arms like people and the leaves are kinda like hair
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I don't know how to do this!!​
saw5 [17]
3x-1=77 (due to exterior alternate angle)
Or, 3x=77-1
or, 3x=76
or, x=76/3
or, x=25.3
6 0
2 years ago
To get from the post office to the library, Sindy walked due north and then due east. The distance Sindy walked east is 20 meter
Sidana [21]
Technically, none of the equations.

The equation you're looking for would be:

x²+(x+20)²=150²


7 0
3 years ago
Read 2 more answers
Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx
shutvik [7]

\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)

Let v=x+y, so that \dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}:

\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1

Now the ODE is separable, and we have

\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx

Integrating both sides gives

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx

For the integral on the left, rewrite the integrand as

\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v

Then

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C

and so

\csc v-\cot v=x+C

\csc(x+y)-\cot(x+y)=x+C

Given that y(0)=\dfrac\pi2, we find

\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1

so that the particular solution to this IVP is

\csc(x+y)-\cot(x+y)=x+1

5 0
3 years ago
Identify two composite numbers that each have 8 as a factor.
Lemur [1.5K]
Two composite numbers that have 8 as a factor are 16 and 24.
7 0
3 years ago
Idk wby it sets it up so weird in word form so imma just put this here
Anit [1.1K]

Answer:

141/2, 279/4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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