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3 years ago

Use the distributive property to write an expression that is equivalent to 6(3 + 4x)

Mathematics

1 answer:

AnnyKZ [126]3 years ago

7 0

18 + 24x

Steps are on paper.

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Mr. Black bought a television set for $450.00. He later sold the television set at a loss of 30%. (a) Calculate the amount of th

fgiga [73]

The amount of the loss exists 1350.

<h3>What is the amount of loss?</h3>

Amount of Loss means an amount equivalent to the outstanding balance of the principal amount, less any amounts recognized by perfecting rights under a security agreement, together with such interest as the executive director shall permit, to a maximum of such interest as may be permitted by rule.

Given: Mr. Black purchased a television set for $450.00. He subsequently sold the television set at a defeat of 30%.

From the given information, we get

$$4500\cdot \frac{30}{100}$

simplifying, we get

$$4500\cdot \frac{30}{100}$

= 1350

Therefore, the amount of the loss exists 1350.

To learn more about opportunity loss refer to:

brainly.com/question/19569042

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3 0

2 years ago

Complete the steps to find the probability that a randomly chosen point on the triangle is in the shaded rectangle. The area of

LUCKY_DIMON [66]

Answer:

150

0.32

Step-by-step explanation:

9 0

3 years ago

Read 2 more answers

X + y = 24

Masja [62]

Answer:

(10, 14)

Step-by-step explanation:

To solve this system let's use substitution:

Solve the first equation for x, obtaining x = 24 - y, and then substitute 24 - y for x in the second equation:

3(24 - y) + 5y = 100

Performing the indicated multiplication, we get:

72 - 3y + 5y = 100

Combining like terms results in 72 - 100 = -2y, or -28 = -2y

Thus, y must be 14.

If y = 14, then the first equation tells us that x = 10.

Check: Is this true? 3(10) + 5(14) = 100 YES

The solution is (10, 14).

What was it about the questions on the best that you were supposed to compare to this solution?

8 0

3 years ago

What is x+2x=100<br><br> what is x?

Vesnalui [34]

I am not sure about the answer but all you have to think about is what is 100 divided by 3

8 0

3 years ago

Read 2 more answers

First question, thanks. I believe there should be 3 answers

zysi [14]

Given: The following functions

$A)cos^2\theta=sin^2\theta-1$ $B)sin\theta=\frac{1}{csc\theta}$ $\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

$\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}$

$\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}$

$\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}$

$\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}$

$\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}$

Hence, the following are identities

$\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}$

The marked are the trigonometric identities

3 0

1 year ago