Answer:
Step-by-step explanation:
Given
Probability of clearing exam in 1 st attempt=0.5
Probability of clearing exam in 2 nd attempt=0.7
Probability of clearing exam in 3 rd attempt=0.8
Probability that she passes the exam
(b)P(Pass qualification on 2nd try|passes qualification)
P(Pass qualification on 2nd try|passes qualification)
P(Pass qualification on 2nd try|passes qualification)
6’000’000.005
Work:
6*1000000 + 5/1000
Answer:
y=-2x+6 and y=4x
Step-by-step explanation:
If you graph these two, the point where the two lines intersect is (1,4).
Answer:
Greater or equal to 20 >/_
Step-by-step explanation:
Answer: 0.82
Step-by-step explanation:
We know that :
For any event A , the probability of not getting A is given by :-
P(not A)= 1- P(A)
Given : The probability that a student chosen at random from your class is a psychology major is P( psychology major) =0.18.
Then, the probability that a student chosen at random from your class is not a psychology major will be :
P(not psychology major)= 1 - P(psychology major)
= 1-0.18=0.82
Hence, the probability that a student chosen at random from your class is not a psychology major= 0.82
