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OleMash [197]
2 years ago
14

Help me please. I need it rn​

Mathematics
2 answers:
cricket20 [7]2 years ago
7 0

Answer:

you can apply percentages knowledge and reverse percentages knowledge. you can look at the formulas and it will be dead easy.

Step-by-step explanation:

melomori [17]2 years ago
4 0

Answer:

We have

selling price=Discount + sales price

discount=discount rate×selling price.

discount=discount /selling price ×100%

Sales price =selling price - discount

Mark of price=mark up price rate ×original price

Selling price:mark of price + original price

commission amount=commission rate ×total sales

simple interest=principal amount ×rate×time/100

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The square below has an area of 22 - 10.2 + 25 square meters.
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Answer:

x = 1.89

Step-by-step explanation:

Solve 22 - 10.2 + 25 to get 36.8 as the square's area.

Set up the equation 36.8 = (-10x + 25)^2 to represent the relationship between one side length and the area.

Reverse the equation to solve for x! Find the square root of both sides to cancel out the exponent. This gets you: 6.07 = -10x + 25.

Subtract 25 from both sides, then divide by -10 to get x by itself.

x = 1.89

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AnnyKZ [126]

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Step-by-step explanation:

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The coordinates of point P on a coordinate grid are (−5, −6). Point P is reflected across the y-axis to obtain point Q and acros
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How to do this question plz answer me ​
Sati [7]

Answer:

d =  \frac{4 - 3c}{c + 1}

Step-by-step explanation:

To make d the subject of formula, we need to rearrange the equation such that we arrive at d= _____.

c =  \frac{4 - d}{d + 3}

<em>Remove the fraction by multiplying (d +3) on both sides:</em>

c(d + 3) = 4 - d

<em>Expand</em><em>:</em>

<em>cd + 3c = 4 - d</em>

<em>Bring</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>d</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>one</em><em> </em><em>side</em><em> </em><em>and</em><em> </em><em>move</em><em> </em><em>the</em><em> </em><em>others</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em> </em><em>side</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em>:</em>

cd + d = 4 - 3c

<em>Factorise</em><em> </em><em>d</em><em> </em><em>out</em><em>:</em>

<em>d(c + 1) = 4 - 3c</em>

<em>Divide</em><em> </em><em>by</em><em> </em><em>(</em><em>c</em><em> </em><em>+</em><em>1</em><em>)</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>

<em>d =  \frac{4 - 3c}{c + 1}</em>

7 0
3 years ago
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