Question

Two students, Abby and Melissa go for a walk. Abby begins walking 30 seconds earlier than Melissa .

Answer 1

Answer:

270 seconds

Step-by-step explanation:

Melissa's time = x seconds

Abby's time = (x + 30) seconds

Abby walks at a speed of 8 feet per second, and Melissa walks at a speed of 9 feet per seconds.

But, speed = $\frac{distance}{time taken}$

For Abby,

8 = $\frac{distance}{(x + 30)}$

distance = 8(x + 30) ................. 1

for Melissa,

9 = $\frac{distance}{x}$

distance = 9x ............. 2

From equations 1 and 2, for the same distance;

8(x + 30) = 9x

8x + 240 = 9x

x = 240 seconds

Abby's time = (x + 30)

                    = (240 + 30)

                    = 270 seconds

So that Abby has been walking for 270 seconds when both students had walked exactly the same distance.