3 years ago

PLEASE ANSWER Answer Choices: 1# 28.26 2# 15.7 3# 12.56 4# 14.13

Mathematics

2 answers:

Setler [38]3 years ago

7 0

Answer: 2

Step-by-step explanation: because it timed the seconde one so that is why its 2

hope the answer helped :)

Alenkinab [10]3 years ago

6 0

The answer is the second one because it matches it

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Find the x-intercepts of the parabola with vertex (1,-108) and y-intercept (0,-105). Write your answer in this form: (X1,y1), (x

Stolb23 [73]

Answer:

(7, 0) and (-5, 0)

Step-by-step explanation:

<u>Vertex form</u>

$y=a(x-h)^2+k$

(where (h, k) is the vertex)

Given:

vertex = (1, -108)

$\implies y=a(x-1)^2-108$

Given:

y-intercept = (0, -105)

$\implies a(0-1)^2-108=-105$

$\implies a(-1)^2=-105+108$

$\implies a=3$

Therefore:

$\implies y=3(x-1)^2-108$

The x-intercepts are when y = 0

$\implies 3(x-1)^2-108=0$

$\implies 3(x-1)^2=108$

$\implies (x-1)^2=36$

$\implies x-1=\pm \sqrt{36}$

$\implies x=1\pm 6$

$\implies x=7, x=-5$

Therefore, the x-intercepts are (7, 0) and (-5, 0)

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2 years ago

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lys-0071 [83]

It would be B)no.

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3 years ago

What are two decimals equivalent to 9.1

Marizza181 [45]

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Step-by-step explanation:

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