All categories

2 years ago

13) A school counselor asked a random sample of seventh- and eighth-

Mathematics

1 answer:

Greeley [361]2 years ago

6 0

Answer:

A. The range of both data sets is 40

Step-by-step explanation:

Range = the maximum value - the minimum value

✔️For the Seventh-Grade Students' data set,

Maximum value = 45

Minimum Value = 5

Range = 45 - 5 = 40

✔️✔️For the Eight-Grade Students' data set,

Maximum value = 45 (the value at the whisker to your far right)

Minimum Value = 5 (value indivl ated by the whisker on your far left)

Range = 45 - 5 = 40

Therefore, the two data sets can be described as having the same range of 40.

You might be interested in

Ezpress 3x + 11/x² + 6x + 9<br>as partial fractions,

andreev551 [17]

Answer:

$\frac{3}{x + 3} + \frac{2}{(x+3)^2}$

Step-by-step explanation:

Given

$\frac{3x + 11}{x^2 +6x + 9}$

Required

Express as partial fraction

$\frac{3x + 11}{x^2 +6x + 9}$

Expand the numerator

$\frac{3x + 11}{x^2 +3x +3x+ 9}$

Factorize

$\frac{3x + 11}{x(x +3) +3(x+ 3)}$

Factor out x + 3

$\frac{3x + 11}{(x +3)(x+ 3)}$

$\frac{3x + 11}{(x +3)^2}$

As a partial fraction, we have:

$\frac{3x + 11}{(x +3)^2} = \frac{A}{x + 3} + \frac{B}{(x+3)^2}$

Take LCM

$\frac{3x + 11}{(x +3)^2} = \frac{A(x+3) + B}{(x + 3)^2}$

Cancel out (x + 3)^2 on both sides

$3x + 11 = A(x+3) + B$

Open bracket

$3x + 11 = Ax+3A + B$

By comparison, we have:

$Ax = 3x$ ===> $A = 3$

$3A + B = 11$

Substitute 3 for A

$3*3 + B = 11$

$9 + B = 11$

Solve for B

$B = 11-9$

$B =2$

Substitute: $A = 3$ and $B =2$ in

$\frac{3x + 11}{(x +3)^2} = \frac{A}{x + 3} + \frac{B}{(x+3)^2}$

$\frac{3x + 11}{(x +3)^2} = \frac{3}{x + 3} + \frac{2}{(x+3)^2}$

Hence, the partial fraction is:

$\frac{3}{x + 3} + \frac{2}{(x+3)^2}$

7 0

1 year ago

If P is between L and A, PL = 6x + 24, PA = 12x - 6 and LA = 30x - 18, then x = ______ and LA = ___&&

levacccp [35]

To solve this problem, we have to use the definition of segment addition.

$LA=PL+PA$

Then, we replace the given expressions

$30x-18=6x+24+12x-6$

Now, we solve for <em>x</em>.

$\begin{gathered} 30x-6x-12x=24-6+18 \\ 12x=36 \\ x=\frac{36}{12} \\ x=3 \end{gathered}$ <h2>Hence, x = 3.</h2>

Let's find LA:

$30x-18=30\cdot3-18=90-18=72$ <h2>Hence, LA measures 72 units.</h2>

7 0

3 months ago

Please help me on this .. Thanks

Fantom [35]

The correct answer among all is D. I'm in K12 8th grade by the way so nice to meet you :)

6 0

2 years ago

Read 2 more answers

2/10 + 7 = 10<br> two over 10 plus 7 equals 10<br> pls help me solve the enquality

koban [17]

If this is a true or false question, it’s false because 2/10 + 7 ≠ 10. the correct inequality would be 2/10 + 7 = 12.

4 0

3 years ago

Read 2 more answers

Someone get me the answers ASAP!! thank you

elena-s [515]

It's 11 because 6+5=11 other words it means it's 11 squares away

3 0

2 years ago