3 years ago

X^ 3 +x^ 2 +4x/x^ 2 +x-2into partialfractions

Mathematics

1 answer:

lawyer [7]3 years ago

6 0

Answer:

x + (4/ x-2) + (2/ x-1)

Step-by-step explanation:

x + (6x/ x^2 + 2x - x -2)

x + (6x/ (x + 2) X (x - 1))

(6x/ (x + 2) X (x - 1))

(A/ x+2) + (B/ x-1)

(6x/ (x + 2) X (x - 1)) = (A/ x+2) + (B/ x-1)

6x = Ax + Bx - A + 2B

6x = (A+B)x + (-A+2b)

{0 = -A+2B

{6 = A+B

(A,B) = (4, 2)

(4/ x+2) + (2/ x-1)

x + (4/ x-2) + (2/ x-1)

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X^ 3 +x^ 2 +4x/x^ 2 +x-2into partialfractions​

X^ 3 +x^ 2 +4x/x^ 2 +x-2into partialfractions