The zeros of a quadratic equation are equal to the x-intercepts of its graph. In other words, you must find the x-value that causes the expression to equal zero. Start by adding 4 to both sides of the equation:
X² - 5x + 4 = 0
Factor the equation:
(x - 1)(x - 4) = 0
Now calculate each piece separately, starting with the first one:
x - 1 = 0
Add 1 to both sides of the equation:
x = 1
We have proven that x = 1. Now calculate the second piece:
x - 4 = 0
Add 4 to both sides of the equation:
x = 4
We have proven that x = 4. Consequently, we have proven that (x = 1) and (x = 4) are the two zeros of this quadratic equation.
I hope this helps!
Answer:
-7x - 6 i think
Step-by-step explanation:
-7x
8-14=6
Answer:471.2
Step-by-step explanation:
V=pie X radius(5)^2 X height(6)
Answer:
True
Step-by-step explanation:
The first derivative tells you the slope of the graph at a specific point. If f'(c) =0, then that means that at f(c), the slope of the graph is 0. It is neither going up nor down
The second derivative tells you the slope of the slope of the graph. If f''(c) < 0, this means that the slope is decreasing. This means that going from the left to f(c), the slope is greater than the slope at f(c), and going from f(c) to the right, the slope is less than the slope at f(c).
Therefore, since the slope at f(c) is 0, the slope is positive to the left of f(c) and negative to the right of f(c). This means that the graph is going up until it hits f(c) and then goes down. Because f(c) is greater than the values to the left of it (because it is going up until it hits f(c)) and the values to the right of it (because it is going down past f(c)), f(c) is a local maximum
