Given sequence:
56, 63, 70,..., 329
First find the common difference:
d=a2-a1
d=63-56
d=7
Formula:
an=a1+(n-1)d
First find the number of terms.
329=56+(n-1)7
329=56+7n-7
329=49+7n
280=7n
40=n
or
n=40
We have to find 40-11=29 th term ( 11 th term from the end)
a29= 56+(29-1)7
a29=56+(28)7
a29=56+196
a29=252
Answer: 252 is 11th term from the end.
Answer:
15.
Step-by-step explanation:
8x - 10 = 110 (vertical angles are equal in measure).
8x - 10+ 10 = 110 + 10
8x = 120
x = 120 /8
x = 15.
Answer:
Firstly
f(x)=3x-2=y then
Interchanging x and y we get
x=3y-2
x+2=3y
y=(x+2)/3
f-1(x)=(x+2)/3
f-1(13)=(13+2)/3
f-1(13)=5