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Leno4ka [110]
3 years ago
8

Can anyone please help me!

Mathematics
2 answers:
Alexxx [7]3 years ago
5 0

Answer:

2

Step-by-step explanation:

(4)(−2)+10

=−8+10

=2

mojhsa [17]3 years ago
5 0

Answer:

it's the option c

it's 2........

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The radius of a circle is 4 m. Find its area in terms of <br> π<br> π.
wlad13 [49]

Answer:

16π

Step-by-step explanation:

Given:

\text{Radius of circle}: 4 \ \text{m}

<u>Formula:</u>

\text{Area of circle} = \pi r^{2}

Replace the radius in the formula:

\implies \text{Area of circle} = \pi (4)^{2}

Evaluate the area:

\implies \text{Area of circle} = \pi (4)(4)

\implies \text{Area of circle} = 16\pi

Since the question says to determine the area in terms of π, the final answer is 16π.

8 0
2 years ago
Conplete the square to solve the quadratic equation. x<br><img src="https://tex.z-dn.net/?f=1%20%7Bx%7D%5E%7B2%7D%20%20-%206x%20
o-na [289]

Answer:

\large\boxed{x=4\pm2\sqrt6}

Step-by-step explanation:

x^2-6x+12=2x+20\qquad\text{subtract}\ 2x\ \text{and}\ 12\ \text{from both sides}\\\\x^2-8x=8\\\\x^2-2(x)(4)=8\qquad\text{add}\ 4^2=16\ \text{to both sides}\\\\x^2-2(x)(4)+4^2=8+4^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-4)^2=24\iff x-4=\pm\sqrt{24}\\\\x-4=\pm\sqrt{4\cdot6}\\\\x-4=\pm\sqrt4\cdot\sqrt6\\\\x-4=\pm2\sqrt6\qquad\text{add 4 to both sides}\\\\x=4\pm2\sqrt6

6 0
3 years ago
The perimeter of a rectangle is greater than or equal to 74 meters.
Ksju [112]

Answer:

12

Step-by-step explanation:

First, multiply the length by two then, subtract the total by the sum, last divide by two.

(25 * 2)

(74 - 50)

(24/2)

Answer = 12

5 0
3 years ago
Read 2 more answers
What is the p(3,1,2) on rolls of a die
Anna35 [415]
Number 3 is 1/6 to role a 1 on the second roll is 1/36= 1/6 X 1/6
to get 2 on the third role is 1/216 so the probability is 1/216 
3 0
3 years ago
If E F = 7 , A C = 16 , and A F = 9
Vilka [71]

Answers:

CB = 14

GF = 8

FB = 9

EF is parallel to CB

====================================

Explanations:

Points E and F are midpoints of their respective sides. They form the midsegment EF. Because EF is a midsegment, A midsegment is half the length of its parallel counterpart, so CB is two times longer than EF. If EF is 7 units long, then CB = 2*EF = 2*7 = 14

For similar reasons, GF is parallel to AC. If AC = 16, then half of that is GF = (1/2)*AC = 0.5*16 = 8.

FB = FA = 9 as these segments have the same single tickmark to indicate they are the same length

EF is parallel to CB because EF is a midsegment, and this is one of the properties of being a midsegment. We can show that quadrilateral EGBF is a parallelogram to help prove this.

8 0
3 years ago
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