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Maksim231197 [3]
3 years ago
9

How do I calculate this distributive property equation:

Mathematics
1 answer:
azamat3 years ago
6 0
6( 5 + 8 )

6 * 13 = 78

Your answer is 78.

Hope this helped!
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Help please!!!!
Mrac [35]

Answer:

a = 2

b = 18

a/b = 1/9

Step-by-step explanation:

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Kathleen had a bag of candy-coated chocolates. Of the 60 candies in the bag, 20% were red, 30% were orange, 30% were green, and
Genrish500 [490]
60*20% are red
60*30% are orange
60*30% are green
60*20% are blue = 12 * 20% = 2.4 blue candy chocolates that are damaged

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What it means by that
denpristay [2]
Example A means

For every #of felt pieces you multiply that by the cost of one piece of felt to see how much you spent

Example
Felts cost $3 a piece
You get 7 pieces

7 x 3= 21

You spent $21 on felt
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Jan plans on running 2,340 miles this year. She plans to run the same number of miles each week. There are 52 weeks in a year.Ho
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The answer is 45 miles a week
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medical tests. Task Compute the requested probabilities using the contingency table. A group of 7500 individuals take part in a
uysha [10]

Probabilities are used to determine the chances of an event

  • The probability that a person is sick is: 0.008
  • The probability that a test is positive, given that the person is sick is 0.9833
  • The probability that a test is negative, given that the person is not sick is: 0.9899
  • The probability that a person is sick, given that the test is positive is: 0.4403
  • The probability that a person is not sick, given that the test is negative is: 0.9998
  • A 99% accurate test is a correct test

<u />

<u>(a) Probability that a person is sick</u>

From the table, we have:

\mathbf{Sick = 59+1 = 60}

So, the probability that a person is sick is:

\mathbf{Pr = \frac{Sick}{Total}}

This gives

\mathbf{Pr = \frac{60}{7500}}

\mathbf{Pr = 0.008}

The probability that a person is sick is: 0.008

<u>(b) Probability that a test is positive, given that the person is sick</u>

From the table, we have:

\mathbf{Positive\ and\ Sick=59}

So, the probability that a test is positive, given that the person is sick is:

\mathbf{Pr = \frac{Positive\ and\ Sick}{Sick}}

This gives

\mathbf{Pr = \frac{59}{60}}

\mathbf{Pr = 0.9833}

The probability that a test is positive, given that the person is sick is 0.9833

<u>(c) Probability that a test is negative, given that the person is not sick</u>

From the table, we have:

\mathbf{Negative\ and\ Not\ Sick=7365}

\mathbf{Not\ Sick = 75 + 7365 = 7440}

So, the probability that a test is negative, given that the person is not sick is:

\mathbf{Pr = \frac{Negative\ and\ Not\ Sick}{Not\ Sick}}

This gives

\mathbf{Pr = \frac{7365}{7440}}

\mathbf{Pr = 0.9899}

The probability that a test is negative, given that the person is not sick is: 0.9899

<u>(d) Probability that a person is sick, given that the test is positive</u>

From the table, we have:

\mathbf{Positive\ and\ Sick=59}

\mathbf{Positive=59 + 75 = 134}

So, the probability that a person is sick, given that the test is positive is:

\mathbf{Pr = \frac{Positive\ and\ Sick}{Positive}}

This gives

\mathbf{Pr = \frac{59}{134}}

\mathbf{Pr = 0.4403}

The probability that a person is sick, given that the test is positive is: 0.4403

<u>(e) Probability that a person is not sick, given that the test is negative</u>

From the table, we have:

\mathbf{Negative\ and\ Not\ Sick=7365}

\mathbf{Negative = 1+ 7365 = 7366}

So, the probability that a person is not sick, given that the test is negative is:

\mathbf{Pr = \frac{Negative\ and\ Not\ Sick}{Negative}}

This gives

\mathbf{Pr = \frac{7365}{7366}}

\mathbf{Pr = 0.9998}

The probability that a person is not sick, given that the test is negative is: 0.9998

<u>(f) When a test is 99% accurate</u>

The accuracy of test is the measure of its sensitivity, prevalence and specificity.

So, when a test is said to be 99% accurate, it means that the test is correct, and the result is usable; irrespective of whether the result is positive or negative.

Read more about probabilities at:

brainly.com/question/11234923

4 0
3 years ago
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