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algol [13]
3 years ago
15

The glass container shown is filled to a height of 2.25 inches. What percentage of the container is filled with sand?

Mathematics
2 answers:
m_a_m_a [10]3 years ago
4 0
1. The volume of the container shown in the figure attached, is:

 V=(5 in)(4.5 in)(3 in)
 V=67. 5 in³

 2. The problem says that the container<span> is filled with sand to a height of 2.25 inches. Then, the volume of the sand into the container is:

 V=</span>(5 in)(4.5 in)(2.25 in)
 V=50.62 in³

 3. Therefore, you have:

 67.5 in³----100%
 50.62 in³---x

 x=50.62x100/67.5
 x=74.99%
<span>
 What percentage of the container is filled with sand?</span> 

 The answer is: 74.99%
dalvyx [7]3 years ago
3 0
How did u make a picture of it plz tell me
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4 2/9 × 6 answer with a mixed number in simplest form. :) Thanks!!!
astra-53 [7]
4 2/9=8/9
8/9 x 6=48/9= 5 3/9
5 3/9= 5 1/3
5 0
3 years ago
A fuel tank contains 1 3/4 gallons of gasoline. Casey adds 33 1/3 gallons of
romanna [79]

Answer:

The gallons of gas the tank contain now is <u>35 1/12</u>.

Step-by-step explanation:

Given:

Fuel tank contains 1 3/4 gallons of gasoline.

Casey adds 33 1/3 gallons of  gasoline to the tank.

Now, to find the total gallons of gas the tank contain.

Converting the mixed fractions into improper.

Gallons of gasoline in fuel tank =1\frac{3}{4}=\frac{7}{4}.

Gallons of gasoline Casey adds =33\frac{1}{3} =\frac{100}{3}.

<u>According to question:</u>

By adding we get the total gallons of gasoline now tank contain:

\frac{7}{4} +\frac{100}{3}

=\frac{7\times 3+100\times 4}{12}

=\frac{21+400}{12}

=\frac{421}{12}

=35\frac{1}{12}

Therefore, the gallons of gas the tank contain now is 35 1/12.

5 0
4 years ago
Please help i wanna make my parents proud !!!!!!
algol13
Why is school so hard
7 0
4 years ago
Need help thank you.
MariettaO [177]

Step-by-step explanation:

3e <= 6

e <= 2 (divide 3 on both sides)

The e-values that satisfy the inequality are:

e = 1 and e = 2.

4 0
3 years ago
Read 2 more answers
Shown here are four frequency distributions. Each is incorrectly constructed. State the reason why.
Tanya [424]

Answer/Step-by-step explanation:

a. The the class width for the 1st, 2nd, 3rd, and 5th row equal 5 in the frequency distribution. Whereas, in the 4th row, the class width is 4 (49 - 45). This makes the construction incorrect.

b. Here, the upper limit of each consecutive class was used as the lower limit if the next class. For example, 9 is a member of the first class, which is the upper limit if the class in the first row, it ought not to be included as a member of the next class in the second row.

c. In the 3rd row, the lower limit of the class should be 133, NOT 138.

d. Different class width were used.

Row 1 class width = 13 - 9 = 4

Row 2 class width = 19 - 14 = 5

Row 3 class width = 25 - 20 = 5

Row 4 class width = 28 - 26 = 2

Row 5 class width = 32 - 29 = 3

8 0
3 years ago
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