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kogti [31]
3 years ago
13

What is the answer to 0.7 × 9​

Mathematics
2 answers:
EastWind [94]3 years ago
8 0

Answer:

6.3

Step-by-step explanation:

Because you use a cacluator.

blondinia [14]3 years ago
6 0

Answer:

\boxed{6,3}

Step-by-step explanation:

0,7 \times 9

= \frac{7}{10} \times 9

= \frac{63}{10}

= 6,3

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Answer:

how many people white chocolate only i'm question is seventeen

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Find Side BC and round to the nearest tenth of a decimal
wel

Answer:

17.0

Step-by-step explanation:

If you take the sin(39) or cos(51), it is equal to BC/27. Multiply by 27 on both sides to get 27cos(51) or 27sin(39)= x. Plug into the calculator, and voila.

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What is 15/50 written in percent
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3 years ago
Farmer Ed has 800 meters of​ fencing, and wants to enclose a rectangular plot that borders on a river. If Farmer Ed does not fen
slega [8]

Answer:

Therefore the dimension of the plot is 400 m × 200 m.

The area of the plot is = 80000 m²

Step-by-step explanation:

Given that a farmer ED has 800 meters of fencing, and wants to enclose a rectangular plot that borders on a river.

Let the length of side along river side be L.

And the width of the plot be be W.

Since the farmer does not fence the river side.

So the length of fence = (L+2w) m

According to the problem,

(L+2w) = 800

⇒L=800 - 2w

Therefore the area of the plot is A = Length ×width

                                                         = (L×W) m²

                                                        =[(800-2W)W] m²

For maximum or minimum \frac{dA}{dW}=0

∴ A =(800-2W)W

⇒A = 800 W -2W²

Differentiating with respect to W

\frac{dA}{dW} = 800 -2.(2W)

\Rightarrow \frac{dA}{dW} = 800 -4W

For maximum or minimum \frac{dA}{dW}=0

\Rightarrow 0 = 800 -4W

\Rightarrow W= \frac{800}{4}

⇒W=200

Again,

\frac{dA}{dW} = 800 -4W

Again differentiating with respect to W

\frac{d^2A}{dW^2}= -4

\therefore[ \frac{d^2A}{dW^2}]_{W=200}= -4

When \frac{d^2A}{dW^2} , then the area A is maximum at W=200.

When \frac{d^2A}{dW^2}>0 , then the area A is minimum at W=200.

Therefore at W= 200 m , the area of the plot maximum at   W=200m

The length of the plot is L = [800- (2×200)] = 400 m

Therefore the dimension of the plot is 400 m × 200 m.

The area of the plot is = (400× 200) m²

                                      = 80000 m²

3 0
3 years ago
Find a second-degree polynomial (that is, an equation of the form y =a + bx + cx2 d that goes through the three points (0, 1), (
Lostsunrise [7]

Answer:

y = 1 - x^2

Step-by-step explanation:

we're given three points (0,1),(1,0) and (-1,0). and and equation of a parabola

y = a + bx + cx^2

we can plug in each of the coordinates, and 3 equations

(x,y) = (0,1)

1 = a + b(0) + c(0)^2

a=1\quad\quad\Rightarrow A

(x,y) = (1,0)

0 = a + b(1) + c(1)^2

a + b + c=0\quad\quad\Rightarrow B

(x,y) = (-1,0)

0 = a + b(-1) + c(-1)^2

a - b + c=0\quad\quad\Rightarrow C

These are are three equations, well we can simultaneously solve them to find the values of a, b and c.

we already found that, a = 1. so we plug this value in the rest of the equations. we'll use equation B.

a + b + c=0

1 + b + c=0

b=-1-c

we can substitute this value of b and a = 1, equation C

a - b + c=0

1 -(-1-c) + c=0

1 +1+c + c=0

2+2c=0

c=-1

we can use this value of c back in b

b=-1-(-1)

b=0

hence our equation of the 2-degree polynomial will be:

y = a + bx + cx^2

y = 1 + (0)x + (-1)x^2

y = 1 - x^2

and this polynomial indeed passes through all the points (0, 1), (1, 0), and (-1, 0).

And since these are the only solutions to the simultaneous equation we solved (i.e. we have single values of a,b and c). there's no other possibility.

8 0
3 years ago
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