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vredina [299]
2 years ago
5

(please help asap!)

Mathematics
1 answer:
Pachacha [2.7K]2 years ago
5 0

Answer:

Step-by-step explanation:

22.50-3.75=18.75

r ≤ 14

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Use the function below to find F(2).<br> F(t) = 2•1/2^3t
navik [9.2K]

Answer:

F(2)= \frac{1}{32}

Step-by-step explanation:

The given function is

F(t) = 2 \cdot \:  \frac{1}{{2}^{3t} }

To find F(2), we substitute t=2 into the function.

This means that wherever we see t, we put 2

F(2) = 2 \cdot \:  \frac{1}{{2}^{3 \times 2} }

We multiply the exponent in the denominator to get:

F(2) = 2 \cdot \:  \frac{1}{{2}^{6} }

We evaluate to get:

F(2) = 2 \cdot \:  \frac{1}{64}

We now cancel the common factors to get:

F(2) = \frac{1}{32}

6 0
3 years ago
Markita bought a roll of carpet that is 8.5 feet wide. The maximum area the carpet will cover is 136 square feet. What is the lo
kenny6666 [7]

Answer:

16 feet in length.

Step-by-step explanation:

In this situation, you are given the area and the width of the full carpet, furthermore, you must reverse the formula for area to find the length, as so:

<u>Area Formula</u>: A=<em> l • w</em>

<u>Given</u>: 136= <em>l</em> • 8.5

<em>l</em> = 136 ÷ 8.5

<em>l</em> = 16 feet

I hope this was helpful!

3 0
3 years ago
In the group of hundred students68 likes football 60 likes volleyball how many likes only football
diamong [38]

Answer:

18 students.

Step-by-step explanation:

Total amount is 100

Take 68 and add to 60 to get 128.

Subtract from both numbers until you get to 50.

68 needs 18 subtracted to get to 50.

60 needs 10 to get to 50.

18 plus 10 is 28, which is the excess.

Here, 18 people like only football.

5 0
3 years ago
Read 2 more answers
Suppose that a standardized biology exam has a mean score of 80% correct, with a standard deviation of 3. The school administrat
NemiM [27]

Answer:

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.

This means that n = 65, \pi = 0.76

99% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 - 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.6236

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 + 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.8964

0.6236*100 = 62.36%

0.8964*100 = 89.64%

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

6 0
2 years ago
What is 1/3 as a decimal value?
Natalka [10]


.33 with a line over the .33 because it is not able to be simplified into a whole decimal when ever both numbers are a factor of 3 besides when it is half that will happen
4 0
3 years ago
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