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vredina [299]
3 years ago
5

(please help asap!)

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
5 0

Answer:

Step-by-step explanation:

22.50-3.75=18.75

r ≤ 14

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In June, Tara gathered data about amusement park attendance on days with different temperatures. Tara used the equation y=−3.5x+
sergij07 [2.7K]

Answer:

25

Step-by-step explanation:

Given the model:

y=−3.5x+400

Number of children in amusement park = y

Temperature = x

On a certain day:

Temperature = 90°F

Number of children in park = 60

Using the model :

The predicted number of children in park when temperature is 90°F would be :

y = - 3.5(90) + 400

y = - 315 + 400

y = 85

Model prediction = 85 children

Actual figure = 60

Residual :

|Actual - predicted | = |60 - 85| = 25 children

6 0
3 years ago
How much of the sphere do you have to paint red so that no matter ow you put a cube in it, some corner touches red?
Triss [41]

Explanation:

To achive that you have to piant a ring in red, which will have its big diameter equal to the sphere diameter and its small diameter equal to the cube diagonal.

The diagonal of the cube can be calculated using Pithagoras:

D^2=L^2+L^2

Where D is the diagonal and L is the side of the cube

4 0
3 years ago
How can I solve 15+50-5/12. this is for fifth grade
Gnom [1K]
Im in fifth grade too. that was on my homework it confused me so much
8 0
3 years ago
A lake has a large population of fish. On average, there are 2,400 fish in the lake, but this number can vary by as much as 155.
AleksAgata [21]

Answer:

Minimum population of fish in lake = 2400 - 155 = 2245

Maximum population of fish in lake = 2400 + 155 = 2555

Step-by-step explanation:

population of fish in lake = 2400

Variation of fish = 155

it means that while current population of fish is 2400, the number can increase or decrease by maximum upto 155.

For example

for increase

population of fish can 2400 + 2, 2400 + 70, 2400 + 130 etc

but it cannot be beyond 2400 + 155.

It cannot be 2400 + 156

similarly for decrease

population of fish can 2400 - 3, 2400 - 95, 2400 - 144 etc

but it cannot be less that 2400 - 155.

It cannot be 2400 - 156

Hence population can fish in lake can be between 2400 - 155 and 2400 + 155

minimum population of fish in lake = 2400 - 155 = 2245

maximum population of fish in lake = 2400 + 155 = 2555

4 0
3 years ago
8.75 x 37.5 and how to do it
salantis [7]
8.75 x 37.5= ? Well all you do is have to line up the decimals and work it out! :) it's simple
3 0
3 years ago
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