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2 years ago

Which function has the same y-intercept as the graph below? -> 12 - 6x 1) y 2) 27+ 3y - 6 3) 6y +18

Mathematics

1 answer:

bagirrra123 [75]2 years ago

7 0

Answer:it’s y+3=6x

Step-by-step explanation:

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Which point is closest to 6.5?<br> A) A <br> B) B <br> C) C <br> D) D

Illusion [34]

That would be B) B
hope it helps

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2 years ago

What is the equation in slope intercept form of the line that passes through the points (-4, 2) and (12, 6)

maksim [4K]

Answer:

search in anywhere

Step-by-step explanation:

or do it in calculator

or ask from your teacher

ans : A) y= 0.25x + 3

B) y= 0.25x - 4.5

C) y= 4x + 18

D) y= 4x - 42

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2 years ago

The functions f(x) and g(x) are described below: f(x) = 7x + 9 g(x) = 7x −4 The graph of g(x) is obtained by shifting down the g

Slav-nsk [51]

Correct Answer:
Option A

Solution:

f(x) = 7x + 9
g(x) = 7x - 4

We can re-write g(x) as:

g(x) = 7x + 9 - 13

Since 7x+9 is equal to f(x), we can write:

g(x) = f(x) - 13

This relation shows that g(x) is obtained by shifting f(x) 13 units vertically down. So the correct answer is option A.

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3 years ago

Find the perimeter of the given triangle

trasher [3.6K]

Here it is given that the triangles ABP and DCR are similars, therefore we use the ratio rule which states that

corresponding sides of similar triangles are in same proprtion .

$\frac{AB}{DC} = \frac{BP}{CR}$

that gives

7/10 = BP/11

7*11=10BP

BP=7.7

Again using the ratio rule

$\frac{AB}{DC} = \frac{AP}{DR}$

7/10 = AP/6

42 = 10AP

AP = 4.2

Perimeter= AB+BP+AP = 7+7.7+4.2 = 18.9

Correct option is A.

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2 years ago

Prove that √2 +√5 is irrational

Sindrei [870]

We have to prove that $\sqrt{2}+\sqrt{5}$ is irrational. We can prove this statement by contradiction.

Let us assume that $\sqrt{2}+\sqrt{5}$ is a rational number. Therefore, we can express:

$a=\sqrt{2}+\sqrt{5}$

Let us represent this equation as:

$a-\sqrt{2}=\sqrt{5}$

Upon squaring both the sides:

$(a-\sqrt{2})^{2}=(\sqrt{5})^{2}\\a^{2}+2-2\sqrt{2}a=5\\a^{2}-2\sqrt{2}a=3\\\sqrt{2}=\frac{a^{2}-3}{2a}$

Since a has been assumed to be rational, therefore, $\frac{a^{2}-3}{2a}$ must as well be rational.

But we know that $\sqrt{2}$ is irrational, therefore, from equation $\sqrt{2}=\frac{a^{2}-3}{2a}$ the expression $\frac{a^{2}-3}{2a}$ must be irrational, which contradicts with our claim.

Therefore, by contradiction, $\sqrt{2}+\sqrt{5}$ is irrational.

4 0

3 years ago

Which function has the same y-intercept as the graph below? -> 12 - 6x 1) y 2) 27+ 3y - 6 3) 6y +18​

Which function has the same y-intercept as the graph below? -> 12 - 6x 1) y 2) 27+ 3y - 6 3) 6y +18