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3 years ago

Solve for x: one over four (4x + 15) = 24

Mathematics

1 answer:

Komok [63]3 years ago

8 0

Answer:

x = 81/4

Step-by-step explanation:

multiply both sides by 4

4x + 15 = 96

subtract 15 from both sides

4x = 81

divide both sides by 4

x= 81/4

i hope that's right

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Each of the following financial products will help you build credit history EXCEPT

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Answer:

Each of the following financisl products will help you build a credit history EXCEPT:

Your answer would be Debit card

Step-by-step explanation:

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2 years ago

A store is having a sale. You can buy 14 cards for $6. What is the cost of 35 cards during this sale?

skad [1K]

Answer:

15$

Step-by-step explanation:

14=$6

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3 years ago

Please help me guys, I need some answers

ella [17]

A one is 12

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Step-by-step explanation:

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2 years ago

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The price of a visit to the dentist is $50. if the dentist fills any cavities an additional charge of $100 per cavity gets added

klio [65]

100x+50= your answer

For example if 3 cavities are filled you would have to multiply 100(3)+50=350

I hope this helps!

6 0

3 years ago

D Evaluate arcsin (6)] at x = 4. dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

4 0

3 years ago