comparing the relation given
thus y= -2x +1 to the general equation of a line
where y= mx + c
where m is the gradient and c is the intercept on the y-axis.
from the question, the gradient is -2 and since the line is perpendicular, the gradient is given as
so substituting the value of m in to the equation
=
as the gradient
equation of line is given by
y - y1 = m( x-x1)
from the question y1= -2 and x1=1
substitute them
y-(-2) = 1/2 (x -1)
y+2 =1/2 (x-1)
multiplying through by 2
2 (y+2) = x-1
2y +4 = x-1
2y =x-1-4
2y =x-5
x -2y -5 = 0
therefore the equation for the line is x-2y -5=0
Given:
In triangle MNO, angle ONM is a right angle. Angle NOM is 40 degrees and angle LMN is 50 degrees.
To find:
The value of cos(M).
Solution:
In a right angle triangle,
Draw a diagram using the given information.
In triangle MNO, angle ONM is a right angle so its opposite side MO is the hypotenuse. For vertex M, MN is the base of the triangle. So,
Therefore, the correct option is B.
To find (f+g)(x), add the equations and simplify by combining like terms.
(x/2)-2+2x^2+x-3
2x^2+ (x/2) +x -5
2x^2 + (1/2)x+x -5
2x^2+ (3/2)x -5
Final answer: C
Remember that (x/2) is the same as (1/2)x. They both represent half of x.
Depends on what pi is.
It could be
50.24 yards (pi is rounded)
OR
16π yards
