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vovangra [49]
3 years ago
11

Solve for r. 5(r - 10) = -51 Enter the answer in the box.​

Mathematics
1 answer:
ANTONII [103]3 years ago
7 0
5(r - 10) = -51
= 5r - 50 = -51
= 5r = -51 + 50
= 5r = -1
= r = -1/5

r = -0.2
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the seventh grade class is putting on a variety show to raise money. it cost 700 dollars to rent the banquet hall that they are
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Answer:

Since the question is partial, i will assume 2 scenarios:

They need to raise 1000 income

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If $1000 as profit:

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ANSWER:

If need to raise atleast $1000 as income, they need to sell 67 tickets.

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3 years ago
Simplify (x*3 +3x*2+6) - (9x*2-5x+7)
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\left[x \right] = \left[ \frac{-1}{4}\right][x]=[​4​​−1​​] = x*3 +3x*2+6) - (9x*2-5x+7
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3 years ago
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The table represents a linear function. A two column table with six rows. The first column, x, has the entries, negative 2, nega
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4 years ago
If the coordinates of the endpoints of a diameter of the circle are​ known, the equation of a circle can be found.​ First, find
Evgesh-ka [11]

Answer:

The equation of the circle is (x+3)^2+(y-5)^2 = 17

Step-by-step explanation:

The complete question is

If the coordinates of the endpoints of a diameter of the circle are​ known, the equation of a circle can be found.​ First, find the midpoint of the​ diameter, which is the center of the circle. Then find the​ radius, which is the distance from the center to either endpoint of the diameter. Finally use the​ center-radius form to find the equation.

Find the center-radius  form of the circle having the points (1,4) and (-7,6) as the endpoints of a diameter.

Consider that, if both points are the endpoints of a diameter, the center of the circle is the point that is exactly in the middle of the two points (that is, the point whose distance to each point is equal). Given points (a,b) and (c,d), by using the distance formula, you can check that the middle point is the average of the coordinates. Hence, the center of the circle is given by

(\frac{1-7}{2}, \frac{4+6}{2}) = (-3,5).

We will find the radius. Recall that the radius of the circle is the distance from one point of the circle to the center. Recall that the distance between points (a,b) and (c,d) is given by \sqrt[]{(a-c)^2+(b-d)^2}. So, let us use (1,4) to calculate the radius.

r = \sqrt[]{(1-(-3))^2+(4-5)^2} = \sqrt[]{17}.

REcall that given a point (x_0,y_0). The equation of a circle centered at the point (x_0,y_0) is

(x-x_0)^2+(y-y_0)^2 = r^2

In our case, (x_0,y_0)=(-3,5) and r=\sqrt[]{17}. Then, the equation is

(x-(-3))^2+(y-5)^2 = (x+3)^2+(y-5)^2 = 17

4 0
3 years ago
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