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Vinvika [58]
3 years ago
8

Find the product. (Do not use spaces in your answer.) d j · d k

Mathematics
2 answers:
PolarNik [594]3 years ago
4 0

Answer:

\displaystyle d^{j + k}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Exponential Rule [Multiplying]: \displaystyle b^m \cdot b^n = b^{m + n}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle d^j \cdot d^k

<u>Step 2: Find</u>

  1. Multiply [Exponential Rule - Multiplying]:                                                         \displaystyle d^j \cdot d^k = d^{j + k}
Sati [7]3 years ago
3 0

Answer:

\huge\boxed{d^j\cdot d^k=d^{j+k}}

Step-by-step explanation:

Use the theorem:

a^n\cdot a^m=a^{n+m}

Why? Look at this example:

2^3\cdot2^4=\underbrace{2\cdot2\cdot2}_{3}\cdot\underbrace{2\cdot2\cdot2\cdot2}_4=\underbrace{2\cdot2\cdot2\cdot2\cdot2\cdot2\cdot2}_{7}=2^7

Therefore

d^j\cdot d^k=d^{j+k}

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