Vertex is directly in middle of directix and focus
distance from 8 to -8 is 16
16/2=8
so 8 below focus (since 8>-8) is the point (0,0
vertex is (0,0)
nice
it opens up because focus is above directix
also it goes up down so
4p(y-k)=(x-h)^2
(h,k) is veretx
we got that (h,k) is (0,0)
and p is distance from vertex to focus which is 8
so
4(8)(y-0)=(x-0)^2
32y=x^2
y=(1/32)x^2
Answer: ( -0.731, 0.682)
Step-by-step explanation:
The unit vector is defined as a vector that points in the same direction as our vector (137 degrees from the x-axis) and has a magnitude of 1.
Knowing the angle, is really simple to do it.
First, we know that for a radius R and an angle A, the rectangular coordinates can be written as:
x = R*cos(A)
y = R*sin(A)
And if we want that the magnitude/modulus of our vector to be 1, then R = 1, and we know that A = 137°
x = 1*cos(137°) = -0.731
y = 1*sin(137°) = 0.682
Then the unit vector is: ( -0.731, 0.682)
Answer:
-3(x + 2)(5x - 3)
Step-by-step explanation:
-15x² – 21x + 18
-3(5x² + 7x - 6)
-3[5x² + 10x - 3x - 6]
-3[5x(x + 2) - 3(x + 2)]
-3(x + 2)(5x - 3)
Answer:9000
Step-by-step explanation:
Answer:
- points on the boundary line: (0, 10), (20, 0)
- solution points not on the boundary line: (100, 100)
Step-by-step explanation:
We cannot tell from the posted picture whether the boundary line is solid or dashed, so the answer above is split into two parts. If the boundary line is solid (x+2y≥20), all three listed points are in the solution set. If the boundary line is dashed (x+2y>20), only (100, 100) is in the solution set.
