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Damm [24]
3 years ago
10

(2) An international call to a certain country costs Rs. 7

Mathematics
1 answer:
KengaRu [80]3 years ago
5 0

Answer:

y = 43

Step-by-step explanation:

Given

First\ Minute = 7

Additional\ Minutes = 4 per minute

Required

Determine the cost of a 10 minutes call

First, we need to determine the expression for the call charges.

Let:

  • x = minutes
  • y = charges

The relationship between x and y is:

y = First\ Minute + Additional\ Minutes(Number\ of\ minutes\ - 1)

i.e.

y = 7 + 4(x - 1)

1 is subtracted from the total minutes because the first minute has a fixed rate.

For a 10 minutes call

x  = 10

y = 7 + 4(x - 1)

y = 7 + 4(10 - 1)

y = 7 + 4*9

y = 7 + 36

y = 43

<em>Hence, the charges for a 10 minutes call is: Rs.43</em>

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Answer: 45%

Step-by-step explanation: To write a fraction as a percent, first remember that a percent is a ratio of a number to 100. If we want to write 9/20 as a percent, we will need to find a fraction equivalent to 9/20 that has a 100 in the denominator. We can do this by setting up a proportion.

\frac{9}{20} = \frac{n}{100}

Now, we can use cross products to find the missing value.

900 = 20n

÷20   ÷20   ← <em>divide by 20 on both sides</em>

<em>   45 = n</em>

Therefore, 9/20 is equal to 45 over 100 or 45%.

<u>___________________________________________________</u>

Answer: 0.45

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How can you use subtraction to complete an addtion pattern
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If you are given a equation like this:

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Which triangles are similar?
likoan [24]

Answer:

option B) ΔABE ∼ ΔADC

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

If two triangles are similar, then its corresponding sides are proportional and its corresponding angles are congruent

In this problem

Triangles ABE and ADC are similar by AA Similarity Theorem

because

m∠ ABE≅m∠ADC

m∠ BAE≅m∠DAC

The corresponding sides are

AB and AD

BE and DC

AE and AC

so

\frac{AB}{AD}=\frac{BE}{DC}=\frac{AE}{AC}

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What is the experimental probability that a 10th-grade student chosen at random has at least one, but no more than two, siblings
Sophie [7]

Answer:

the experimental probability is 70%

Step-by-step explanation:

PLEASE HELP, TIMEDThe table shows the results of a survey in which 10th-grade students were asked how many siblings (brothers and/or sisters) they have.

What is the experimental probability that a 10th-grade student chosen at random has at least one, but no more than two, siblings?

To the nearest whole percent, the experimental probability is

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b. 70%

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We are given to find

the experimental probability that a 10th-grade student chosen at random has at least one, but no more than two, siblings

we know that

probability = ( number of favourable outcomes)/ ( total possible outcomes)

a 10th-grade student chosen at random has at least one, but no more than two, siblings

so, there can be one or two siblings

so, total number of such students =18+10=28

Number of favourable outcomes =28

total number of students =4+18+10+8=40

so, total favourable outcomes =40

now, we can find probability

p=\frac{28}{40}\\\\p=\frac{28}{40}\times 100\\\\p=70

So,

Therefore, the experimental probability is 70%

7 0
3 years ago
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