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Naily [24]
3 years ago
10

Which values of a, b, and c correctly represent the answer in simplest form? 3 =a O a=38.0= 14.0=1 a=1.0= 14.C = 38 O a= 1.5=7.C

= 19 O a = 19.0= 7.0= 1​
Mathematics
1 answer:
katrin [286]3 years ago
5 0

Answer:

The answer could be A) or D) because the zero acts as a place holder. Its a little easier to derive it if you have a bigger decimal

Step-by-step explanation:

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Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

5 0
3 years ago
First I will build the envelope. For this, I am using a rectangular piece of material 28m long and 12m wide. Out of this materia
RUDIKE [14]

Answer:

3.728 cm²

90

Step-by-step explanation:

To built the envelope I am using a rectangular piece of material 28 m long and 12 m wide.  

Out of this material, I have to cut patches that are 1/12 the length and 2/15 the width of the whole material.

So, the length of the patches is 28 \times \frac{1}{12} = 2.33 m and the width of the patches is 12 \times \frac{2}{15} = 1.6 m.

Therefore, the area of the patches is (1.6 × 2.33) = 3.728 m² each. (Answer)

Now, the area of the rectangular piece of material is (28 × 12) = 336 m²

Hence, \frac{336}{3.728} = 90.37 ≈ 90 such patches can be made out of the whole material. (Answer)

3 0
3 years ago
PLEASEEE HELP NOBODY IS ANSWERING ME RIGHT ALSO I AM USING UP THE LAST OF MY PoiNTS TO ASK THIS QUESTION !!! Determine the verte
irga5000 [103]

Answer:

D.

Step-by-step explanation:

with questions like this try using Desmos

8 0
3 years ago
Read 2 more answers
Please answer both
iogann1982 [59]
Every function is a relation because the numbers have relationships but not every relation is a function because for it to be a function there has to be one y fo every x if any x(input) has more than one y(output) it's not a function
3 0
3 years ago
Jonah finished 24 math problems in
8_murik_8 [283]

Answer:

3 hours

Step-by-step explanation:

In an hour there are 60 minutes to find the unit rate of problems per minute you divide 60/24 and get 2.5 multiply 2.5 by 72 get 180 in minutes that is 3 hours

3 0
3 years ago
Read 2 more answers
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