Do any of yall go to hamshire fannett school district in fannett near beaumont

How far below the bridge will kate eventually be hanging, once she stops oscillating and comes finally to rest? assume that she

shepuryov [24]

The distance below the bridge that kate will eventually be hanging, once she stops oscillating and comes finally to rest is: d = mg/k + L.

<h3>Distance</h3>

LetForce exerted by a spring=F=kx

Let x = (d – L)

Let d= Total length of the bungee cord

Let set this equal to the gravitational force

F(spring) = k(d – L)

F(gravity) = mg

Hence:

k(d – L) = mg

(d – L) = mg/k

d = mg/k + L

Inconclusion the distance below the bridge that kate will eventually be hanging, once she stops oscillating and comes finally to rest is: d = mg/k + L.

Learn more about distance here:brainly.com/question/15159264

6 0

2 years ago

2.17 LAB: Word frequencies - methods Write a program that reads a list of words. Then, the program outputs those words and their

pickupchik [31]

Using the knowledge in computational language in JAVA it is possible to write a code that reads a list of words.

<h3>Writting the code in JAVA:</h3>

import java.util.*;

//class name LabClass

public class LabClass{

//function getFrequencyOfWord with array wordList, ListSize and currWord as parameter

public static int getFrequencyOfWord(String[] wordsList, int ListSize, String currWord){

int frequency = 0;

//for loop for iteration

for(int i=0; i<ListSize; i++){

//if current word matches with words present in list

//then increase the frequency by 1

if(wordsList[i].compareTo(currWord)==0){

frequency++;

}

//return frequency at last

return frequency;

}

//main function

public static void main(String[] args) {

//creating object of Scanner class

Scanner sc = new Scanner(System.in);

int size;

//asking user to input size of list

System.out.println("Enter the size of list :");

size = sc.nextInt();

//creating array of same size as user input size

String[] wordList = new String[size];

sc.nextLine();

//asking user to input array elements

System.out.println("Enter list elements one by one :");

for(int i =0; i<size; i++)

{

wordList[i] = sc.nextLine();

}

System.out.print("\n");

sc.close();

//calling function getFrequencyOfWord in every iteration by passing

//required arguments to it

for(int i=0; i<size; i++)

{

String currWord = wordList[i];

int count = getFrequencyOfWord(wordList, size, currWord);

//printing result

System.err.println(currWord + " : " + count);

}

}

See more about JAVA at brainly.com/question/12978370

#SPJ1

3 0

2 years ago

Skill plans

Gala2k [10]

Answer:

3500 cm/min

Explanation:

speed= distance/time

speed= 6300/1.8

= 3500

8 0

2 years ago

Whats the best answer for this equation: 4(b - 4) ; b = 5

icang [17]

The answer to this is 4

8 0

3 years ago

The drivetrain engages the gears in the transmission. True False

Rainbow [258]

Answer:

A transmission is a machine in a power transmission system, which provides controlled application of the power. ... In British English, the term transmission refers to the whole drivetrain, including clutch, gearbox, prop shaft (for rear-wheel drive), differential, and final drive shafts.

Explanation:

8 0

3 years ago