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Sonja [21]
2 years ago
9

The diagram below is a scale drawing of a farmer's vegetable garden, where the length is 12 inches and the width is 8

Mathematics
1 answer:
Travka [436]2 years ago
5 0

Answer:

length times width

divided by 1.5

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Diego hopes to attend a public Texas university in a city more than 300 miles from his home. The website lists the following cos
Dovator [93]

ANSWER:

Total cost for Diego to attend university,

$11,850 + $10,645 + $1,780 + $1,864 + 1,602

  • $22,495 + $5,246
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Now for 4 years, we have to multiply it by 4.

  • $27,741 × 4
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3 years ago
Which equation best models the fine schedule for overdue books? , where x is the cost in cents for a book that is y days overdue
earnstyle [38]

x is the independent variable, and in this scenario, the independent variable is the number of days overdue. So the best equation would be where x is the number of days overdue, and y is the cost in cents.


Example equation:



x = number of days overdue

y = cost in cents

z = total price

z = yx

4 0
3 years ago
K^2+k=0 what does k=
FinnZ [79.3K]

Answer:

k = K^2

Step-by-step explanation:

Subtract  K^2 from both sides of the equation.

6 0
3 years ago
What two integers have a sum of -7 and a product of -18?
Elis [28]

Answer:

-9 and 2

Step-by-step explanation:

-9 x 2

5 0
2 years ago
Read 2 more answers
Write an equation of a line parallel to the line
Airida [17]

Answer: y = -2x - 5

Step-by-step explanation:

The condition for parallelism is that m1 = m2 ie, the gradient of the two lines must be equal.

from the equation given,

y =  -2x  + 8, m1 = -2, therefore m2 = -2. Since the two line passes through the coordinate of (-1, -3 ) , we substitute  for x and y in the equation of a line

y = mx + c to get the value of  , the y - intersect.

-3 = -2 x -1 + c

-3 = 2 + c

solve for c

c = -3 - 2

c = -5.

now , to have the equation of the line , we put c = -7 into the equation

y = mx + c

y = -2x  - 5

Therefore the equation of the line parallel to the line

y = -2x + 8 is

y = -2x - 7

4 0
3 years ago
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