Answer:
Please post one by one answer
Replace a and b with their given values:
(2(3/5) -1/3) / -6.75/15
2 x 3/5 = 6/5
6/5 - 1/3 = 18/15 - 5/15 = 13/15
13/15 / -6.75/15 = 13/15 x 15/-6.75 = (13 x 15) / (15 x -6.75) = 195/-101.25 = -1 25/27
Answer: -1 and 25/27
The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
Learn more about work done here:
brainly.com/question/25970931
#SPJ1
