Find < JKL (angle) *
1 answer:
Answer:
- 132°
Step-by-step explanation:
See attached
<h3>Given </h3>- JM = 27, ML = 16, JL = 46, NK = 15, m∠KLM = 48°, m∠JKM = 78°, and m∠MJL = 22°
- m∠JKL
<u>JKLM is a parallelogram and therefore has equal opposite angles:</u>
- ∠JKL = ∠JML and ∠KJM = ∠KLM
<u>Sum of all four is 360°:</u>
- 2m∠JKL + 2m∠KLM = 360°
- m∠JKL + m∠KLM = 180°
- m∠JKL + 48° = 180°
- m∠JKL = 180° - 48°
- m ∠JKL = 132°
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The bearing of the airport from the plane is 245°
Step-by-step explanation:
The bearing of a point from a location is given by the angle in degrees of rotation from the Northern direction of the location to the direction of the location of the point
The given bearing of the plane from the airport = 65°
Therefore, the direction of the plane from the Northern direction of the airport = 65°
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