The answer would be 5.291 10 to the power of 12
Answer:
2
Step-by-step explanation:
Let's solve the given system of equations.
<u>Given system</u>
x +3y= 10 ----(1)
-2x -2y= 4 ----(2)
From (2):
-2(x +y)= 4
Dividing both sides by -2:
x +y= -2 ----(2)
Thus, options 3 and 4 are incorrect as x +y≠ -2.
(1) -(2):
(x +3y) -(x +y)= 10 -(-2)
Expand:
x +3y -x -y= 10 +2
2y= 12
Divide both sides by 2:
y= 12 ÷2
y= 6
Substitute y= 6 into (2):
x +6= -2
x= -6 -2
x= -8
Options (1) and (2) differs only by the value of the expression of -x +y. Thus, let's find its value in the given system of equations.
-x +y
= -(-8) +6
= 8 +6
= 14
Thus, option 2 is the correct option.
The linear equation in standard form is:
6x - 7y = -11
Which is the last option.
<h3>
How to get the equation of the line?</h3>
The line in slope-intercept form is written as:
y = a*x + b
We can see that the line passes through the points (-3, -1) and (1/2, 2), then the slope is:
Then we can write:
y = (6/7)*x + b
To find the value of b, we use the first point. It means that when x = -3, the value of y is -1, then we get:
-1 = (6/7)*-3 + b
-1 + 18/7 = b
-7/7 + 18/7 = b
11/7 = b
Then the equation is:
y = (6/7)*x + 11/7
If we multiply both sides by 7 we get:
7y = 6x + 11
Now we move the term with "x" to the left:
7y - 6x = 11
That is the line in standard form.
If we multiply both sides by -1, we get the last option:
6x - 7y = -11
If you want to learn more about linear equations:
brainly.com/question/1884491
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the answer for your question is A :>
Answer:
hey, there!
Step-by-step explanation:
The given is a point (-6,8) through which a line passes. And is perpendicular to the line y = 2x-4
The equation for point (-6,8) is,
(y-8)= m1(x+6)...........(i)
and given equation is y = 2x-4............(ii)
Now, from equation (ii).
slope (m2)= 2 { as equation (ii) is in the form of y= mx+c where m is a slope}.
Now, For perpendicular,
m1×m2= -1
m1×2= -1
Therefore, m1 = -1/2.
Putting, the value of m1 in equation (i).
(y-8) = -1/2×(x+6)
2(y-8)= -1(x+6)
2y - 16 = -x -6
x+2y-10 = 0......... is the required equation.
Hope it helps...
