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2 years ago

What do i do please help!

Mathematics

1 answer:

Art [367]2 years ago

8 0

Answer:

Step-by-step explanation:

this is confusing b/c they are asking about two trains traveling at differnt speeds, but.. if you put the speeds together and make one train... imaginary.. ofc... traveling at the speed of both trains combined... when will it be 50 miles from the station?

maybe you can solve that? I'll solve it below.. but.. if you can.. try it now, on your own

below is my answer... don't look until you have solved yours :P

80+70= 150kph

when will this have traveled 50Km?

you may be able to see that it will take 1/3 of an hour to travel 50 km

so 60 minutes times 1/3 = 20 minutes :)

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Helllllppp please asap

BartSMP [9]

Answer:

1). a = 9.42 m

2). b = 6.37 m

3). c = 4.48 m

Step-by-step explanation:

In the figure attached,

By applying tangent rule in triangle ADE,

tan47 = $\frac{h}{c}$

c = $\frac{h}{\text{tan}47}$

c = $\frac{4.8}{\text{tan}47}$

c = 4.476

c ≈ 4.48 m

Now we apply the same rule in triangle ACE,

tan37° = $\frac{h}{b}$

b = $\frac{h}{\text{tan}37}$

b = $\frac{4.8}{1.0724}$

b = 6.37 m

Now apply the tangent in triangle ABE,

tan27° = $\frac{h}{a}$

a = $\frac{h}{\text{tan}27}$

a = $\frac{4.8}{0.5095}$

a = 9.42 m

5 0

2 years ago

John has a box that is in the shape of a cube (i.

Artemon [7]

A box (cube) has all equal edges or sides (s), thus the volume (v) of the cube is:
$v = {s}^{3} \\ 27 \: {in}^{3} = {s}^{3} \\ \sqrt{( {s}^{3}) } = \sqrt{( {27in}^3)} \\ s = 3 \: in$
So since each side or edge around is 3 in, then the length around the square bottom of the box = 4×3 = 12 in

5 0

2 years ago

Calculate: 1/1x3+1/3x5+…+1/47x49

shtirl [24]

Answer:

24/49

Step-by-step explanation:

3 0

2 years ago

1. What is( - 1/2 + 2) 2. 4( 1/2+5/4) + (-5) (please answer, I will mark brainliest) :)

Ulleksa [173]

$\longrightarrow (-\dfrac{1}{2} +2)$

$\longrightarrow (-\dfrac{1}{2} +\dfrac{4}{2} )$

$\longrightarrow \dfrac{-1+4}{2}$

$\longrightarrow \dfrac{3}{2}$

$\sf \bold{\longrightarrow 1\dfrac{1}{2}}$ (final answer)

$\longrightarrow \sf 4(\dfrac{1}{2} +\dfrac{5}{4} ) + (-5)$

$\longrightarrow \sf 4(\dfrac{2}{4} +\dfrac{5}{4} ) + (-5)$

$\longrightarrow \sf 4(\dfrac{7}{4} ) + (-5)$

$\longrightarrow \sf 7-5$

$\longrightarrow \bold{\sf 2}$ (final answer)

4 0

2 years ago

HELP Determine whether the relation is a function y=2w=2

nexus9112 [7]

Answer:

Hi there!

I might be able to help you!

It is NOT a function.

Determining whether a relation is a function on a graph is relatively easy by using the vertical line test. If a vertical line crosses the relation on the graph only once in all locations, the relation is a function. However, if a vertical line crosses the relation more than once, the relation is not a function. X = y2 would be a sideways parabola and therefore not a function. Good test for function: Vertical Line test. If a vertical line passes through two points on the graph of a relation, it is not a function. A relation which is not a function. The x-intercept of a function is calculated by substituting the value of f(x) as zero. Similarly, the y-intercept of a function is calculated by substituting the value of x as zero. The slope of a linear function is calculated by rearranging the equation to its general form, f(x) = mx + c; where m is the slope.

A relation that is not a function

As we can see duplication in X-values with different y-values, then this relation is not a function.

A relation that is a function

As every value of X is different and is associated with only one value of y, this relation is a function.

Step-by-step explanation:

It's up there!

God bless you!

3 0

3 years ago