Question

Quadrilateral ABCD is similar to quadrilateral EFGH.

Answer 1

Answer:

$s = 11$

Explanation:

Given

The attachment completes the question.

Required

Find s

Because ABCD and EFGH are similar, then:

$\frac{AB}{CD} = \frac{EF}{GH}$

From the attachment:

$AB = 2s$

$CD = 3s - 3$

$EF = 5.5$

$GH = 7.5$

So, we have:

$\frac{2s}{3s - 3} = \frac{5.5}{7.5}$

Cross Multiply

$2s * 7.5 = 5.5(3s - 3)$

Open bracket

$2s * 7.5 = 5.5*3s - 5.5*3$

$15s = 16.5s - 16.5$

Collect Like Terms

$15s - 16.5s = - 16.5$

$-1.5s = - 16.5$

Make s the subject:

$s = \frac{-16.5}{-1.5}$

$s = \frac{16.5}{1.5}$

$s = 11$

Hence, the value of s is 11 m